Question

The angle of elevation to the top of a very tall building is found to be 13° from the ground at a distance of 1 mi from the base of the building. Using this information, find the height h of the building. (Round your answer to the nearest foot.)

Answer 1

Tan(Θ)=(h/distance from base)
Θ=13 degrees, 1mile=5280 ft
tan(13)=(h/5280 ft)
5280tan(13)=h
h=1218.984049
h=1219 ft