Need some help! Graph the equations y=3x-5 and x+3y=6 on the same xy-plane. What is significant about these two lines? (Explain
your answer)
Thanks!
Thanks!
1 answer:
To solve this, we must first put both lines in Slope Intercept Form (y=mx+b where m is the slope and b is the y-intercept).
y=3x-5 is already in SIF, so we only need to work on the other one.
x+3y=6
-x -x
3y=-x+6
/3 /3
y=-1/3x+2
Now we have both equations in slope intercept form, so we can start graphing from the y-intercepts and just follow the slopes.
When we do this, we will see that the lines meet at an exactly 90° angle. When a pair of lines does this, it means they are perpendicular.
Below I have attached an image that has both lines graphed so that you may visualize it. The green dots show the slopes, while the highlighted areas show the y-intercepts. Note that the lines intersect at a 90° angle, making them perpendicular.
y=3x-5 is already in SIF, so we only need to work on the other one.
x+3y=6
-x -x
3y=-x+6
/3 /3
y=-1/3x+2
Now we have both equations in slope intercept form, so we can start graphing from the y-intercepts and just follow the slopes.
When we do this, we will see that the lines meet at an exactly 90° angle. When a pair of lines does this, it means they are perpendicular.
Below I have attached an image that has both lines graphed so that you may visualize it. The green dots show the slopes, while the highlighted areas show the y-intercepts. Note that the lines intersect at a 90° angle, making them perpendicular.
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Answer:
x>14
Step-by-step explanation:
X-3> 11
Add 3 to each side
X-3+3> 11+3
x > 14
The hole is open at 14 since it is greater than
( it would be closed if it were ≥) The line goes to the right since it is greater than
