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Lana71 [14]
3 years ago
14

Need some help! Graph the equations y=3x-5 and x+3y=6 on the same xy-plane. What is significant about these two lines? (Explain

your answer)
Thanks!

Mathematics
1 answer:
adell [148]3 years ago
6 0
To solve this, we must first put both lines in Slope Intercept Form (y=mx+b where m is the slope and b is the y-intercept).

y=3x-5 is already in SIF, so we only need to work on the other one.

 x+3y=6
-x       -x
 3y=-x+6
 /3      /3
 y=-1/3x+2

Now we have both equations in slope intercept form, so we can start graphing from the y-intercepts and just follow the slopes.

When we do this, we will see that the lines meet at an exactly 90° angle. When a pair of lines does this, it means they are perpendicular.

Below I have attached an image that has both lines graphed so that you may visualize it. The green dots show the slopes, while the highlighted areas show the y-intercepts. Note that the lines intersect at a 90° angle, making them perpendicular.

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Evaluate this question
cestrela7 [59]

Answer:

d.

Step-by-step explanation:

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3 0
3 years ago
Can someone please help me with this problem? An explanation would be great, but it can be short. Thank you!!
ss7ja [257]

We are given two points: (4, -8) and (8, 5)

General equation of a line: y = mx + c

First find m (the gradient). There is a formula for this: (change in y)/(change in x) = gradient

(5 - -8) / (8 - 4) = (13) / (4) = 3.25 = m

y = 3.25x + c

Now we need to find c (the y-intercept; the value of y when x=0).

Substitute in any one of the coordinates - let's use (8, 5)

(5) = 3.25(8) + c

(5) = 26 + c

c = -21

The equation of the line: y = 3.25x - 21


I think that this answer is correct - sorry if it seems rushed.

Hope this answer helps :)

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!1111 I REALLY NEED HELP I A, BEGGIN YOU GUYS!!!!!!!!!!!!!!!!!!!!!!!!!!! ILL GIVE BRAINLIEST AND
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

4y - 2(5 - y + 4) = 4y - 2(9 - y)

                         = 4y + 9*(-2) - y *(-2)

                         = 4y  - 18 + 2y      {Combine like terms 4y and 2y}

                         = 6y - 18

6y - 18 = 6*y - 6*3

           = 6(y - 3)

6y- 18 =  2 *3y - 2*9

          = 2(3y -9)

2(3y - 9) and 6(y- 3 ) are equivalent to 4y - 2(5- y +4)

Others are not equivalent

3 0
3 years ago
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