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murzikaleks [220]

3 years ago

14

(३) एक शब्द में उत्तर लिखो:

1 answer:

o-na [289]3 years ago

8 0

करना चाहिए। वे तुम्हें नष्ट कर देंगे।

आप कोई मौका नहीं खड़े हैं। तुम

उसके हाथ पर मर जाओगे। पछताना

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The length L of a rectangle is 4 units more than its width W. The rectangle's are is 252 square units. A) Write the equation tha

jek_recluse [69]

Answer:

w=14

l=18

Step-by-step explanation:

To find the dimensions, create an equation for its area and solve for each using the area formula A = l*w. The dimensions given are A = 252, w for width and l= w+4 (4 more than the width).

$A = l*w\\252 = (w+4)*w\\252 = w^2+4w\\252+4 = w^2 +4w +4\\256 = (w+2)^2\\\sqrt{256} =\sqrt{(w+2)^2} \\16 = w+2\\16 = w+2\\14= w\\$

The width is 14 so the length is l=w+4 or l= (14)+4 =18

3 0

3 years ago

Calculate the volume of each of the following prisms.

Mariana [72]

Answer:

The Rectangular prism in the top-left corner is 11,760. The top-middle rectangular prism is 7,938. The top-right rectangular prism is 4,851. The shape that is orange and pink I don't know what it is. The triangular prism on the middle of the page is 11.781. The blue cylinder is 38,936. The green rectangular prism is 23,125. The "clear" rectangular prism on the bottom row is 31,668. The rectangular prism in the bottom right corner is 14,688. That is all, I'm almost 100 percent sure they are all right!

3 0

2 years ago

A public health organization reports that 40%of baby boys 6-8 months old in the United

Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

$P(X > 4) = 1 - P(X \leq 4)$

In which:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061$

$P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403$

$P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150$

$P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502$

Hence:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325$

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675$

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106$

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

$P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001$

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

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4 0

1 year ago

Write an equation for which 0 is a solution

masha68 [24]

Answer:

x-y=0

Hope this helped

4 0

2 years ago

What adds to -288 and adds to -41?

inna [77]

-329 hood this helps

6 0

2 years ago

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