Question

Samantha has a pig enclosure that is 4 feet by 6 feet in her backyard. She wants to double the area of the enclosure by increasing the length and the width by the same amount. By how many feet will the length and the width be increased? Round to the nearest hundredth if necessary

Answer 1

Answer:

The length and the width will be increased by 2 feet to double the area for pg enclosure.                      

Step-by-step explanation:

We are given the following in the question:

Dimension of pig enclosure:

Length = 6 feet

Width = 4 feet

Samantha wants to double the area by increasing equal amount of length and width.

Area of pig enclosure =

$A = \text{Length}\times \text{Width}\\A = 6\times 4\\A = 24\text{ square feet}\\A' = 48\text{ square feet}$

Let the length and width be increased by x feet.

Then, we can write

$48 = (6+x)(4+x)\\48 = 24+6x+4x + x^2\\x^2 + 10x-24 = 0\\(x + 12)(x - 2)=0\\x = -12, x = 2$

Thus, the length and the width will be increased by 2 feet to double the area for pg enclosure.