Answer:
a. 1/2 + 9/10 = 5/10+9/10 = 14/10 = 7/5 = 1 2/5 meters or ribbon
b. 5/8 = 15/24, 7/12 = 14/24 Jeff jogged longer and by 1/24 kilometers
c. 3/9 = 6/18. 15/18-6/18 = 9/18 = 1/2 left.
Hope this helps :)
Step-by-step explanation:
A= (2,-2)
B= (-2,-2)
C=(2,4)
D=(-2,2)
if this helped Brainliest me on this answer it helps alot :))
9514 1404 393
Answer:
3. m∠A < 80°
Step-by-step explanation:
The exterior angle NGS, marked as 80°, has a measure that is the sum of the measures of the remote interior angles: GAN, GNA.
If we assume that angle measures cannot be zero, then we must have ...
m∠A +m∠N = 80°
m∠A = 80° -m∠N
Since m∠N > 0, the measure of angle A must be less than 80°.
This conclusion matches choice 3.
9514 1404 393
Answer:
A. 7 seconds
Step-by-step explanation:
We assume your factored equation is something like ...
h(t) = -16t(t -7)(t +2)
The time it takes the ball to reach the ground is the positive value of t that makes a factor zero:
t -7 = 0 ⇒ t = 7
The ball will land on the ground in 7 seconds.
1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
