Fill in the Blanks

Show a graph Slope function of -1 with a y intercept of 3

castortr0y [4]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

We have m = -1 and b = 3. Substitute:

$y=-1x+b\to y=-x+3$

The graph is a straight line. Therefore we need only two points to plotting the graph.

One we have, the y-intercept (0, 3). Calculate other point.

Put any value of x to the equation of a line and calculate the value of y:

For x = 3:

$y=-3+3=0\to(3,\ 0)$

6 0

3 years ago

Simplify -4 + (-3) + 6.

Svetlanka [38]

Answer:3/6 in simplest fraction form is 1/2.

Step-by-step explanation:EASY and my chanel is FireFlameZero if u can check dat out

6 0

2 years ago

8. There are 4,800 plastic spoons in a case.

g100num [7]

Answer:

Each box has 800 spoons.

Step-by-step explanation:

4800/6=800

7 0

3 years ago

Evaluate <br> 3^-3*3^4*3*3^-5

miss Akunina [59]

To multiply exponents with like bases, simply add the exponents...

3^-3 × 3^4 × 3 × 3^-5 =

add exponents across, remember just 3 means 3^1.

-3 + 4 + 1 + -5 = -3

answer is 3^-3

8 0

3 years ago

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

5 0

3 years ago