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baherus [9]
4 years ago
8

Determine the number of significant digits in each measurement.

Mathematics
1 answer:
Marina CMI [18]4 years ago
5 0
4 significant figures. All figures are significant because the zeros are in between two significant digits
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What I am really in need of help. If anyone answers this I will award 60 points to anyone!
Vesna [10]
There is usually calculator that will solve it for you look for them just plug the question in and it can show the steps too
7 0
3 years ago
URGENT!! 100 POINTS, BRAINLIEST AS WELL
Olenka [21]

Answer:

C

Step-by-step explanation:

Notice that there is a little triangle formed by the lines on the right side of the diagram.

Let's find the angle measures of the triangle. One of them has a supplementary angle of 96 degrees, which means that the actual interior angle is 180 - 96 = 84 degrees.

Another angle has a supplementary angle of 137, which means that the actual interior angle of the triangle is 180 - 137 = 43 degrees.

Finally, we have the expression 2x - 23, which is an exterior angle. By definition, this exterior angle is equal to the sum of the interior angles of the triangle that do not include its supplementary angle. In other words:

2x - 23 = 84 + 43

Now we just solve for x:

2x - 23 = 84 + 43 = 127

2x = 127 + 23 = 150

x = 150/2 = 75 degrees

The answer is 75 degrees, or C.

8 0
3 years ago
Read 2 more answers
Explain why it is important to line up decimal points when you are adding and subtracting decimals. Use the problem 6.32 – 0.5 i
Mazyrski [523]

Answer:

Kindly check explanation

Step-by-step explanation:

When performing addition and subtraction of decimals, it is important to arrange the numbers being added or subtracted such that the decimal points are in line. This is particularly important so that the place value of the numbers are in accord.

To simplify, when then decimals are in line, then the tenth value of the first number will be added to the tenth value of the second. Without this arrangement, one might be adding the hundredth placed value to the tenth or unit value which is mathematically incorrect and will yield a wrong result.

For instance :

6.32 - 0.5

Here, when the decimal point of each number is in line, the tenth placed value of the first number (3) matches the tenth placed number of the second number (5) and all others also fall in place automatically.

____6.32

- ___0.5

________

___ 5.82

________

4 0
3 years ago
More help plzzz!!!!!!
pantera1 [17]

200 grams, b/c 1.6 kg converted to grams is 1600grams, divided by 8 pots; therefore 200g

5 0
3 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
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