Answer:
Step-by-step explanation:
Slope: -3
y-intercept: -2 (y-intercept is where a line cross the y-axis, vertical line)
Pencil on the y-intercept, three down and one to the right, then trace the line from -2 on the y-axis.
I'm assuming that x is part of the data set, and, with x, the mean equals 105. To find the value of x, you must add all the data values together to get 544+x (you still don't know what x equals). Then put 544+x over how many days values there are, including x (there are 6). You should have 544+x/6. Now, as this is how you would calculate the mean if you knew what x was equal to, you must set it equal to the mean, since you know what it is (105). You should now have 544+x/6 = 105. You have your equation set up--now you just have to solve it. I would multiply by 6 on both sides to get rid of the 6 on the left side. You would then have 544+x = 630. I would finally subtract 544 from both sides to get x = 86. Your final answer is x = 86.
Tamam hocam nasılsınız hocam proje konularını da bir insan değilim ki bir şey olmaz ya o yüzden bir insan bir
var ama ben bir insan bir arar
The additional interest Benson pay each month is $750 if he invested at the rate of 2% for one year, option (b) is correct.
<h3>What is simple interest?</h3>
It is defined as the interest on the based on the principal amount, it does not include the compounded amount. The interest calculate on the initial amount or borrowed amount.
We know the formula for the simple interest is given by:
I = PRT
Where I is the simple interest.
P is the principal amount
R is the rate of interest
We have in the question:
I = $180
R = 2% = 0.02
T = 1 year
Put the above values in the formula, we get:
180 = P(0.02)(1)
P = $9000
The additional interest Benson pay each month is:
= 9000/12
= $750
Thus, the additional interest Benson pay each month is $750 if he invested at the rate of 2% for one year option (b) is correct.
Learn more about the simple interest here:
brainly.com/question/22621039
145 divided by 7 =20.71
a little sketch on my answer <span />
