Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
The pattern on the table is x increases:
- The sine of x increases
- The cosine of x increases
- The function sin²(x) + cos²(x) remains constant
<h3>How to describe the pattern?</h3>
The functions on the table of values are:
sin(x), cos(x) and sin²(x) + cos²(x)
To describe the pattern, we simply observe how the values of the function change, as x increases.
As x increases, on the table:
- The sine of x increases
- The cosine of x increases
- The function sin²(x) + cos²(x) remains constant
Read more about trigonometry functions at:
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Answer:
f(0) = 3
Step-by-step explanation:
Step 1: Distribute
f(x) = -3x + 3
Step 2: Plug in
f(0) = -3(0) + 3
f(0) = 3
Answer:
F because you cannot prove that any of the angles are the same with only one set of parallel lines
