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3 years ago

25 POINTS I NEED HELP

Mathematics

1 answer:

koban [17]3 years ago

7 0

We know that his woodshed is a parallelepiped, and 8' is the depth, 16' is the lenght and 6' is the height.

A cord of wood is 4' high, 4' deep and 96" long.

96" = 8'

We find the volume of his woodshield.

V = h*d*l = 168*6 = 768 cubic feet

Find the volume of a cord

4*4*8 = 128 cubic feet

Do the ratio: 768/128 = 6

His woodshield can hold 6 cords.

For the second question, simply do a multiplication.

If 1 cord is $120, how much are 6?

120*6 = $720

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( 5x + 685 ) + ( 12x - 106 ) = 2500

uysha [10]

Answer:

x = 113

Step-by-step explanation:

( 5x + 685 ) + ( 12x - 106 ) = 2500 ( 685 - 106 = 579)

17x + 579 = 2500

17x = 2500 - 579

17x = 1921

x = 1921 / 17

x = 113

3 0

3 years ago

Element X is a radioactive isotope such that every 26 years, its mass decreases by half. Given that the initial mass of a sample

SSSSS [86.1K]

Answer:

It will take 15.029 years for element X to reach mass of 260 grams

Step-by-step explanation:

The half life period of radioactive element X is 26 years

The initial mass of radioactive element X is 260 grams

Elapsed time = half life * log (beginning amount /ending amount)/log 2

Substituting the given values, we get

Elapsed time = 26 * log (390/260)/log 2

= 15.209 years

8 0

2 years ago

Classify the following triangle. Check all that apply.

Arlecino [84]

Scalene,Acute i think it is haha

5 0

3 years ago

Read 2 more answers

Rita and Tina each make $11 an hour working as cashiers at a supermarket. Last week, Rita worked r hours while Tina worked t hou

Sonbull [250]

Rita = (11r + 32)
Tina = 11t

5 0

3 years ago

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

ANSWER:

$x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}$

3 0

11 months ago