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zimovet [89]
3 years ago
11

Find the probability that a randomly selected student drives to school.

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

the answer is 40 percent

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Maria told Patrick that her quarter weighs less than what a nickel weighs because 0.2 has fewer digits than .18. How can Patrick
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If you add a zero at the end it is easier to understand. 0.20 > 0.18 because 20 is greater than 18
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4 years ago
The average human body temperature is 98.6, write 98.6 as a mixed number
Delicious77 [7]

Multiply it by 100 to give you a fraction over 100 then see how many times the numerator (the top number) goes into the denominator (the bottom number) to get a mixed number

 

7 0
4 years ago
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Please Help, I have to show my work too. 20 pts.
pav-90 [236]

Answer:

1.8148

Step-by-step explanation:

\frac{823543 * 531441}{794280046581}

\frac{437664515463}{794280046581}

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1)Find the angle of elevation of the sun from the ground when a tree that is
KIM [24]

Answer:

\theta=41.18^{\circ}

Step-by-step explanation:

Given that,

The height of the tree, h = 14 ft

The height of the shadow, b = 16 ft

We need to find the angle of elevation of the sun from the ground. Let the angle be θ. We can use trigonometry to find it. So,

\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{14}{16}\\\\\theta=41.18^{\circ}

So, the required angle of elevation of the sun is equal to 41.18^{\circ}.

7 0
3 years ago
Suppose that P(n) is a propositional function. Determine for which nonnegative integers n the statement P(n) must be true if a)
wel

Solution :

a). $P(0)$ is true

Then ,$P(0+2)=P(2)$ is true.

         $P(2+2)=P(4)$ is true

          $P(4+2)=P(6)$ is true.

Therefore, we see that $P(n)$ is true for all the even integers : $\{0, 2,4,6,...\}$

b). $P(0)$ is true

Then ,$P(0+3)=P(3)$ is true.

         $P(3+3)=P(6)$ is true

          $P(6+3)=P(9)$ is true.

Therefore, we see that $P(n)$ is true for all the multiples of 3 : $\{0, 3,6,9,12,...\}$

c). $P(0)$ and $P(1)$ is true, then $P(0+2)=P(2)$ is true

$P(1)$ and $P(2)$ is true, then $P(1+2)=P(3)$ is true.

$P(2)$ and $P(3)$ is true, then $P(2+2)=P(4)$ is true.

So, we observe that  $P(n)$ is true for all the non- negative integers : $\{0, 1,2,3,4,5,6,...\}$.

d). $P(0)$ is true,

   So, $P(0+2)$ and $P(0+3)$ is true or $P(2)$ and $P(3)$ is true.

   Now,   $P(2)$ is true.

Again, $P(2+2)$ and $P(2+3)$ is true or $P(4)$ and $P(5)$ is true.

   Now, $P(3)$ is true.

Again, $P(3+2)$ and $P(3+3)$ is true or $P(5)$ and $P(6)$ is true.

Thus,

$P(n)$ is true for all the non- negative integers except 1 : $\{0, 2,3,4,5,6,...\}$.

3 0
3 years ago
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