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Inessa [10]
3 years ago
15

If the m∠2 = 40, what is the m∠5?

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
7 0

Answer: answer is 140 on gradpoint.com

77julia77 [94]3 years ago
5 0

Answer: The answer is 100.

Step-by-step explanation: 40 divided by 2 = 20

x=20

20x5=100

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Find 64.9% of 77. Round to the nearest tenth.
eduard

Answer:

64.9% of 77

Step-by-step explanation:

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3 years ago
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A manufacturer earns Rs4500 in the first month and Rs 6000 in second month. On plotting these points a manufacturer observes a l
UkoKoshka [18]

Answer:

f(x) = 1500x +3000

Step-by-step explanation:

Given

Represent the months with x and the earnings with y.

So:

(x_1,y_1) = (1,4500)

(x_2,y_2) = (2,6000)

Required

Determine the linear function

First, calculate slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{6000 - 4500}{2 - 1}

m = \frac{1500}{1}

m = 1500

The equation is then calculated using:

y = m(x - x_1) + y_1

y = 1500(x - 1) + 4500

y = 1500x - 1500 + 4500

y = 1500x +3000

As a function, we have:

f(x) = 1500x +3000

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2 years ago
Help me plz I’ll give brainlist plz!!!!!!!!!!!
marishachu [46]

Answer:

answer is 10/3 thats the answer

5 0
2 years ago
If f(x) = f(x)g(x), where f and g have derivatives of all orders, show that f'' = f ''g + 2f 'g' + fg''.
Nadya [2.5K]
Differentiating once, we have

f'(x)=f'(x)g(x)+f(x)g'(x)

Differentiating again,

f''(x)=f''(x)g(x)+f'(x)g'(x)+f'(x)g'(x)+f(x)g''(x)
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as needed.
5 0
2 years ago
Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
Bettina          3,425 yards     13 minutes, 12 seconds
Chandra       8,214 feet        0,195 hours
Divya            1,62 miles        732 seconds

To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

First you need to convert the data to obtain the rate in miles per second.

These are the main conversion identities:

1 mile = 5280 feet

1 mile = 1760 yards

1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

Arabella:

rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet)  =

= 0.00244 mile/second

Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

Bettina:

13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds

rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

Chandra:

rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

= 0.00222 seconds

Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

Divya:

rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
6 0
3 years ago
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