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Alla [95]
3 years ago
5

Rewrite using negative exponent: 5/x^2

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0

Answer:  The given expression can be rewritten using negative exponent as 5x^{-2}.

Step-by-step explanation:  We are given to rewrite the following expression using negative exponent :

E=\dfrac{5}{x^2}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following property of exponents :

\dfrac{1}{x^a}=x^{-a}.

So, from (i), we get

E=\dfrac{5}{x^2}=5\times x^-2=5x^{-2}.

Thus, the given expression can be rewritten using negative exponent as 5x^{-2}.

STALIN [3.7K]3 years ago
5 0
The rule for negative exponents is that if the exponent is negative to begin with, in order to make it negative, you put it into the denominator of a fraction, and raise it to whatever the power is.  To go from positive exponents (those that are already in the denominator), move it up to the numerator and make the exponent negative. So your solution would be 5x^-2
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y = 2/3x + 6

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If two lines are parallel, that means their slopes are the same.

Rewrite 2x - 3y = 15 to y = 2/3x - 5

The slope is 2/3, so the answer should have a slope of 2/3 as well.

The equation is now y = 2/3x + b

To find b, substitute (-3,4)

y = 2/3x + b

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The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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The randomly sampled 400 dogs from homes where an herbicide was used on a regular basis, diagnosing lymphoma in 230 of them.

This means that:

p_h = \frac{230}{400} = 0.575, s_h = \sqrt{\frac{0.575*0.425}{400}} = 0.0247

Of 200 dogs randomly sampled from homes where no herbicides were used, only 25 were found to have lymphoma.

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The confidence interval is:

p \pm zs

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The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

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