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Nezavi [6.7K]
3 years ago
14

Hey guys can u help me i took like 3 hours to know the answer but i cant get it pls help me thank you

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

iajjsbaksskdddkldjdsd

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Ksivusya [100]

Answer:

me

Step-by-step explanation:

pleas i'm begging you

5 0
3 years ago
In a certain city of several million people, 7.7% of the adults are unemployed. If a random sample of 300 adults in this city is
Lilit [14]

Answer: 0.2643

Step-by-step explanation:

Given : The proportion of  adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

\mu=np=300\times0.077=23.1

\sigma=\sqrt{np(1-p)}=\sqrt{300\times0.077(1-0.077)}\\\\=4.61749932323\approx4.62

Now, using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponding to 26 will be :-

z=\dfrac{26-23.1}{4.62}\approx0.63

Using standard distribution table for z , we have

P-value=P(z\geq0.63)=1-P(z

=1-0.7356527=0.2643473\approx0.2643

Hence, the probability that at least 26 in the sample are unemployed  =0.2643

6 0
2 years ago
Who did you vote for and are you scared :(
kkurt [141]

Answer:

Trump

Step-by-step explanation:

5 0
2 years ago
A population of size 3,624 grows at a rate of 3% per year, compounded continuously. How big will the population be in 2 years?
rodikova [14]

Answer:

Step-by-step explanation:

The continuous compound formula is

y=Pe^{rt where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:

y=3624e^{(.03)(2)}\\y=3624e^{.06}\\y=3624(1.061836547)\\y=3848.09

which would probably round to just 3848 people.

8 0
2 years ago
Using chain rule, what is the derivative of sin(arcsin(x))
sergey [27]
Chain rule
y=f(g(x))
y´=(d f(gx)/d g)(d g/d x)

or

y=y(v)   and v=v(x), then dy /dx=(dy/dv)(dv/dx)

in our case:
y=sin (v)
v=arcsin(x)

dy/dv=d sin (v)/dv=cos (v)=cos(arcsin(x)
dv/dx=d arcsin(x)/dx=1/√(1-x²)

dy/dx=[cos (arcsin(x))]/√(1-x²)

Answer: d sin(arcsin(x))/dx=[cos (arcsin(x))]/√(1-x²)
7 0
2 years ago
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