$709.21
$361.36 for week one + $347.85 for week two = $709.21 total for both weeks
Answer:
Hi! The answer to your question is 
Step-by-step explanation:




☆*: .。.。.:*☆☆.*: .。..。.:*☆☆*: .。.。.:*☆☆.*: .。..。.:*☆
☁Brainliest is greatly appreciated!☁
<em>Hope this helps!!</em>
<em>- Brooklynn Deka</em>
Answer: 0.0136
Step-by-step explanation:
Given : Mean : 
Standard deviation : 
Sample size : 
The formula to calculate the z-score :-

For x = 24

The p-value = 
Hence, the probability that the sample mean age for 50 randomly selected women to marry is at most 24 years = 0.0136
Answer:
0.5
Step-by-step explanation:
Let D be the event of selecting a marble with dots.
Let P be the event of selecting a purple marble.
The probability of selecting a marble with dots, P(D)=0.2
The probability of selecting a marble that is both purple and has dots, 
We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)
By the definition of conditional probability:

The probability of selecting a purple marble given that the marble has dots on it is 0.5.
Answer:
the answer is d
Step-by-step explanation:
d