Answer:
$ 37.5
Step-by-step explanation:
It is given :
Price of the dress in the market = $ 50
The shopkeeper a discount percentage = 25%
Therefore the discount amount is = 25 % of 250

= 12.5
Therefore the sale price of the dress is = 50 - 12.5
= 37.5
Therefore the sale price is $ 37.5
Answer:
x² + 10x + 25
Explanation:
Before we begin, remember the following:
(a + b)(a + b) = (a + b)² = a² + 2ab + b²
Now, for the given we have:
(x + 5)(x + 5)
We can note that the two brackets are identical.
Therefore, we can apply the above rule as follows:
(x + 5)(x + 5) = (x + 5)²
= (x)² + 2(x)(5) + (5)²
= x² + 10x + 25
Hope this helps :)
Answer:
x=2
Step-by-step explanation:
-3(2-x)=4-(3x+1)
-6+3x=4-3x-1
-3/3=-6x/3
2=x
Hello there!
1.) To start, first know that a cube has the same height, length, and width, meaning that all of the dimensions are 5-in. Then, when you slice it in half, this would mean that you have now reduced the width to half of its original. This would mean that the width is now 2.5 while the height and length remain 5.
Now that you have this information, you can now find the surface area by using this formula:
A= 2lw+2lh+2hw
Now plug in your values:
A=2(5)(2.5)+2(5)(5)+2(5)(2.5)
This would simplify to:
A=25+50+25
A=100 in squared
Therefore, the surface area of the two pieces are 100 inches squared.
2.) To start, first plug the measurements of the tank into the cylinder volume formula:
V=
r^2h
V=
(2.75)^2(10)
V= 237.58 cubic feet
Now, we must find how long it will take the tank to empty if the rate is 3.7 cubic feet per minute so divide the volume (in feet) by the rate:
237.58/3.7= 64.2108...
Rounded to the nearest hundredth, it would take approximately 64.21 minutes to empty the take when it is full.
:)
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Answer:
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

(Right tailed test at 5% level)
Mean difference = 0.2
Std error = 
Z statistic = 1.0540
p value = 0.145941
since p >alpha we do not reject H0.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.