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mixas84 [53]
3 years ago
11

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne

t in a typical week. The mean of the sample observations was 12.9 hours.
(a) The sample standard deviation was not reported, but suppose that it was 6 hours. Carry out a hypothesis test with a significance level of 0.05 to decide if there is convincing evidence that the mean time spent using the Internet by Canadians is greater than 12.7 hours. (Use a statistical computer package to calculate the P-value. Round your test statistic to two decimal places and your P-value to three decimal places.)

t= P-value =

State the conclusion in the problem context.

a. Reject H0. We have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
c. Do not reject H0. We have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
d. Reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

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Step-by-step explanation:

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So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

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