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matrenka [14]
3 years ago
8

For a big football game, Joseph made a sandwich that was 72 inches long. By the end of the first quarter, 2 feet had been eaten.

How many feet of the sandwich were remaining at the end of the first quarter? A. 4 B. 3 C. 10 D. 8
Units of Length
1 mile (mi) = 1,760 yards (yd)
1 mile = 5,280 feet (ft)
1 yard (yd) = 3 feet (ft)
1 foot = 12 inches (in.)
Mathematics
2 answers:
Dovator [93]3 years ago
6 0

Answer:

72-2=70ft

Step-by-step explanation:

antiseptic1488 [7]3 years ago
3 0

Answer:

A.4

Step-by-step explanation:

Because 72/12=6, and 2 feet and been eaten, so you subtract 6-2=4

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Answer:

Step-by-step explanation:

8.4625025e+20

7 0
3 years ago
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A certain scrapbook kit costs $26, and there is 6% sales tax.
Alex17521 [72]

Answer:

1% of 26 is $0.26 so 6% of $26 is $1.56

Step-by-step explanation

The answer for this is very easy all you have to do is for the first half you take 1% and turn it into a decimal which is 0.01 then you multiply 0.01 by 26 which is 0.26. For the next half of the problem, it's just like the last one you take 6% and turn it into a decimal which is 0.06 then you multiply 0.06 by 26 which is 1.56 and then you have your answer.

3 0
3 years ago
An item is priced at $14.86. If the sales tax is 8%, what does the item cost including sales tax?
geniusboy [140]

Answer:

The answer is A.

Step-by-step explanation:

8 0
4 years ago
I would like some help thank you :)
pantera1 [17]

Answer:

\angle AE = 32^{\circ}

\angle EAD = 212^{\circ}

\angle BE = 133^{\circ}

\angle BCE = 227^{\circ}

\angle AED = 180^{\circ}

\angle BD = 79^{\circ}

Step-by-step explanation:

The central angle of a circle is equal to 360º, whose formula in this case is:

\angle AB + \angle BC + \angle CD + \angle DE + \angle EA = 360^{\circ}

In addition, the following conditions are known from figure:

\angle BC = 47^{\circ}, \angle DE = 148^{\circ}

\angle DE + \angle EA = 180^{\circ}

\angle CD + \angle DE = 180^{\circ}

\angle AB + \angle BC + \angle CD = 180^{\circ}

Now, the system of equations is now solved:

\angle EA = 180^{\circ}-\angle DE

\angle EA = 180^{\circ}-148^{\circ}

\angle EA = 32^{\circ}

\angle CD = 180^{\circ}-\angle DE

\angle CD = 180^{\circ}-148^{\circ}

\angle CD = 32^{\circ}

\angle AB = 180^{\circ} - \angle BC - \angle CD

\angle AB = 180^{\circ}-47^{\circ}-32^{\circ}

\angle AB = 101^{\circ}

The answers are described herein:

\angle AE = 32^{\circ}

\angle EAD = 212^{\circ}

\angle BE = 133^{\circ}

\angle BCE = 227^{\circ}

\angle AED = 180^{\circ}

\angle BD = 79^{\circ}

7 0
3 years ago
Simplify the algebraic expression 8y-2(y+4)
Goshia [24]

Answer:

6y -8

Step-by-step explanation:

8y-2(y+4)

Distribute the 2

8y -2y -8

Combine like terms

6y -8

7 0
3 years ago
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