A computer simulation tossed a 10-faced die 5 times. How many possible outcomes exist?
2 answers:
Answer: There exists 100000 possible outcomes.
Step-by-step explanation: Given that a computer simulation tossed a 10-faced die 5 times.
We are to find the number of possible outcomes that exists.
Since there are 10 faces of the die, so we have 10 possible options for each of the 5 tosses.
Therefore, the total number of possible outcomes is
Thus, there exists 100000 possible outcomes.
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Answer:
Hence, the set that represent a negative linear association between x and y is:
Set A.
Step-by-step explanation:
We are given 4 sets of data as:
<u>Set A </u>
x 1 2 3 4 5 6 7 8 9
y 10 9 8 7 6 5 4 3 2
<u>Set B </u>
x 1 2 3 4 5 6 7 8 9
y 3 4 5 6 7 8 9 10 11
<u>Set C </u>
x 1 2 3 4 5 6 7 8 9
y 8 6 5 4 3.5 3 2.5 2 2
<u>Set D </u>
x 1 2 3 4 5 6 7 8 9
y 1 2.5 2.5 3 4 5 6 8 9
We are asked to determine the set which represent negative linear association between x and y?
- Clearly in Set B and Set D the values of y keeps on increasing as the value of x increases; hence they both represent a positive linear association between x and y.
- In set C the relationship is non-linear though it is negative.
- Clearly in Set A we could see that the the y is related to x as:
y=11-x or y= -x+11.
Hence, clearly we could see that the relationship is linear and also negative as the value of y keeps on decreasing with increasing x.
Hence, the set that represent a negative linear association between x and y is:
Set A.
