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3 years ago

6

NEED HELP PLEASE ASAP THIS A FUNCTION HELP!!!

1 answer:

andrey2020 [161]3 years ago

4 0

You have to deal with this type of question step by step. Firstly, you can figure out all the unknown values (such as sqrt x-3), by substituting x for 19, as you are trying to figure out f(x) when x=19. Therefore:
x+2=21
sqrt(x-3)=sqrt(19-3)=sqrt 16=4
Now the equation is easier to handle:
3/21 - 4
We can write this as 3/21 - 4/1 , which equals -27/7.

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3 years ago

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3 years ago

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3 years ago

`4x+3y=27` Solve the equation for y.

Minchanka [31]

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3 years ago

The sum of the first number cubed and the second number is 500 and the product is a maximum.

soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

$x^3+w=500$

We can then express y as:

$w=500-x^3$

We can express their product as:

$x(500-x^3)=500x-x^4$

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

$\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}$

Then we solve for the value of x where f'(x) = 0.

$\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}$

Then we use x = 5 to solve for the second number, w.

$\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}$

Therefore, the two numbers are 5 and 375.

3 0

1 year ago