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3 years ago

NEED HELP PLEASE ASAP THIS A FUNCTION HELP!!!

Mathematics

1 answer:

andrey2020 [161]3 years ago

4 0

You have to deal with this type of question step by step. Firstly, you can figure out all the unknown values (such as sqrt x-3), by substituting x for 19, as you are trying to figure out f(x) when x=19. Therefore:
x+2=21
sqrt(x-3)=sqrt(19-3)=sqrt 16=4
Now the equation is easier to handle:
3/21 - 4
We can write this as 3/21 - 4/1 , which equals -27/7.

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50 POINTS!

Elodia [21]

the error in this flowchart is:second one.

Point L is equidistant from endpoints J and K, not J and N.

Answer:

Solution given:

LM which is a perpendicular bisector of segment JK,

it means JN=JK

o JL and KL are equal in length, according to the definition of a midpoint.

True

O Point L is equidistant from endpoints J and K, not J and N.False.

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3 years ago

How long is a guy wire reaching from the top of a 6ft. Pole to a point on the ground 4ft. From the pole

dlinn [17]

Answer:

the guy wire is 7.211 ft long

Step-by-step explanation:

Notice that we are in the presence of a right angle triangle formed by: the height (the standing 6 ft pole), the base (the distance from the pole to the anchoring point on the ground), and the actual guy wire. See attached image for reference.

Notice that since pole and ground are perpendicular to each other (at 90 degrees) , the guy wire forms what is called the "hypotenuse" (longest side) of the right angle triangle. We can therefore use the Pythagorean Theorem to solve this problem with the formula for the hypotenuse:

$Hypotenuse=\sqrt{side1^2 +side2^2} \\Hypotenuse= \sqrt{6^2+4^2}\\Hypotenuse=\sqrt{36+16} \\Hypotenuse=\sqrt{52} \\Hypotenuse=7.2111\, ft$

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