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AVprozaik [17]
3 years ago
7

The tables below show four sets of data:

Mathematics
2 answers:
Lena [83]3 years ago
8 0

Answer:

it is set a

Step-by-step explanation:

vovangra [49]3 years ago
3 0

Answer:

Hence, the set that represent a negative linear association between x and y is:

Set A.

Step-by-step explanation:

We are given 4 sets of data as:

<u>Set A  </u>

x 1 2 3 4 5 6 7 8 9  

y 10 9 8 7 6 5 4 3 2

<u>Set B  </u>

x 1 2 3 4 5 6 7 8 9  

y 3 4 5 6 7 8 9 10 11

<u>Set C  </u>

x 1 2 3 4 5 6 7 8 9  

y 8 6 5 4 3.5 3 2.5 2 2

<u>Set D  </u>

x 1 2 3 4 5 6 7 8 9  

y 1 2.5 2.5 3 4 5 6 8 9

We are asked to determine the set which represent negative linear association between x and y?

  • Clearly in Set B and Set D the values of y keeps on increasing as the value of x increases; hence they both represent a positive linear association between x and y.
  • In set C the relationship is non-linear though it is negative.
  • Clearly in Set A we could see that the the y is related to x as:

         y=11-x or y= -x+11.

Hence, clearly we could see that the relationship is linear and also negative as the value of y keeps on decreasing with increasing x.

Hence, the set that represent a negative linear association between x and y is:

Set A.

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Consider the probability that greater than 77 out of 131 computers will crash in a day. Assume the probability that a given comp
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Answer:

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

Step-by-step explanation:

Let <em>X</em> = number of computers that will crash in a day.

The probability of a computer crashing in a day is, <em>p </em>= 0.99.

A random sample of <em>n</em> = 131 is selected.

A random computer crashing in a day is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 131 and <em>p</em> = 0.99.

But the sample size is quite large, i.e. <em>n</em> > 30.

So the distribution of <em>X</em> can be approximated by the normal distribution if the following conditions are fulfilled:

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Check whether the conditions satisfy or not:

np=131\times 0.99=129.69>10\\n(1-p)=131\times (1-0.99)=1.31

The second condition is not fulfilled.

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

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