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3 years ago

The tables below show four sets of data:

Mathematics

2 answers:

Lena [83]3 years ago

8 0

Answer:

it is set a

Step-by-step explanation:

vovangra [49]3 years ago

3 0

Answer:

Hence, the set that represent a negative linear association between x and y is:

Set A.

Step-by-step explanation:

We are given 4 sets of data as:

Set A

x 1 2 3 4 5 6 7 8 9

y 10 9 8 7 6 5 4 3 2

Set B

x 1 2 3 4 5 6 7 8 9

y 3 4 5 6 7 8 9 10 11

Set C

x 1 2 3 4 5 6 7 8 9

y 8 6 5 4 3.5 3 2.5 2 2

Set D

x 1 2 3 4 5 6 7 8 9

y 1 2.5 2.5 3 4 5 6 8 9

We are asked to determine the set which represent negative linear association between x and y?

Clearly in Set B and Set D the values of y keeps on increasing as the value of x increases; hence they both represent a positive linear association between x and y.
In set C the relationship is non-linear though it is negative.
Clearly in Set A we could see that the the y is related to x as:

y=11-x or y= -x+11.

Hence, clearly we could see that the relationship is linear and also negative as the value of y keeps on decreasing with increasing x.

Hence, the set that represent a negative linear association between x and y is:

Set A.

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antoniya [11.8K]

Answer:qjs

Step-by-step explanation:

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2 years ago

For which value of X is the row in the table of values incorrect? The function is the quadratic function Y=3/4x^2

svet-max [94.6K]

Answer:

The row with x = 2 and y = 4 is incorrect. The y value should be y = 3 when x = 2.

==============================================================

Explanation:

Fractions can be a bit of a pain, so I'm going to be converting to decimal form to help with the computation; however, I will convert the y value results to mix number form so that it matches what the table shows.

Keep in mind that 3/4 = 0.75 when you use a calculator or long division. So a number like 2.75 means 2 & 3/4 (two and three quarters)

---------------

Let's check the first row. Plug in x = 0 and it leads to...

y = (3/4)*x^2

y = (3/4)*0^2

y = (3/4)*0

y = 0.75*0

y = 0

This shows us that row 1 is correct. When x = 0, y = 0 leading to (x,y) = (0,0).

-------------

Repeat the same basic outline of steps, but now use x = 2

y = (3/4)*x^2

y = (3/4)*2^2

y = (3/4)*4

y = 0.75*4

y = 3

So instead of 4, the proper y value is y = 3 when x = 2. This means row 2 is the answer (the row that has the incorrect values).

-------------

For the sake of completeness, let's see if the third row is correct or not. Plug in x = 3

y = (3/4)*x^2

y = (3/4)*3^2

y = (3/4)*9

y = 0.75*9

y = 6.75

y = 6 & 3/4

We see that x = 3 points to y = 6 & 3/4, so we have the correct values in this row. We can cross this off the list of choices.

-------------

Finally, let's check x = 5

y = (3/4)*x^2

y = (3/4)*5^2

y = (3/4)*25

y = 0.75*25

y = 18.75

y = 18 & 3/4

We get the proper y value. So we can also cross this off the list.

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3 years ago

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Nana76 [90]

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Step-by-step explanation:

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mojhsa [17]

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Answer:

Step-by-step explanation:

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7 0

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