Answer:
1 pear = $0.75; 1 orange = $0.65
Step-by-step explanation:
(1) 3P + 4O = 4.85
(2) 3P + 10O = 8.75 Eqn (2) - Eqn (1)
3P + 10O – 3P – 4O = 8.75 – 4.85 Combine like terms
6O = 3.90 Divide each side by 6
O = $0.65 Substitute into Eqn (1)
3P + 4×0.65 = 4.85
3P + 2.60 = 4.85 Subtract 2.60 from each side
3P = 2.25 Divide each side by 3
P = $0.75
Oranges cost $0.65 each and pears are $0.75 each
we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
A set of 3 nonzero whole numbers say (a,b,c) that form the sides of a right triangle and follow the pythagorous theorem

are called a Pythagorean Triple
The example of Pythagorean Triplet are
(3,4,5), (5,12,13) ,(8,15,17), etc.
Hence
A set of 3 nonzero whole numbers that form the sides of a right triangle are called a Pythagorean Triple.