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olya-2409 [2.1K]
3 years ago
13

Laura received a box of chocolates for her birthday. The chocolates in the box have five different fillings. The table below sho

ws how many chocolates with each type of filling are in the box.
The chocolates are all the same shape and size. Laura does not like coconut or toffee. What is the probability that Laura will pick a chocolate from the full box that has a filling she does like?

Probability _______________________

In the space below, explain the process you used to determine your answer

Please help :c somebody!

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
In this question we are asked to find the ratio of the number of chocolates which Lauren liked and the total of chocolates.

We know she doesn't like coconut and toffee, so she likes caramel, mint and cherry. When we count the ones she liked, we got 16+12+14=42.

When we add to find how many chocolates are there, we got 16+10+12+14+8=60.

To find the ratio we need to divide the first one and the second one: \frac{42}{60} = \frac{7}{10} = 0.7 is our probability.
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Please help I’m so confused
kari74 [83]

1) angle MIG = angle JIH

2) angle PMJ = angle QHG

3) angle MJI

4) 100

6 0
3 years ago
If three pears and four oranges cost $4.85 and three pears and ten oranges cost $8.75 what is the cost of a pear and an orange
marishachu [46]

Answer:

1 pear = $0.75; 1 orange = $0.65

Step-by-step explanation:

(1)               3P +  4O = 4.85

(2)              3P + 10O = 8.75                 Eqn (2) - Eqn (1)

3P + 10O – 3P – 4O = 8.75 – 4.85     Combine like terms

                           6O = 3.90                 Divide each side by 6

                             O = $0.65              Substitute into Eqn (1)

           3P + 4×0.65 = 4.85

               3P + 2.60 = 4.85                 Subtract 2.60 from each side

                           3P = 2.25                Divide each side by 3

                            P = $0.75

Oranges cost $0.65 each and pears are $0.75 each

4 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
2 years ago
I need the answer fast pls
musickatia [10]

Answer:

I think D

Hope this helps!!

4 0
3 years ago
Read 2 more answers
A set of 3 nonzero whole numbers that form the sides of a right triangle are called a Pythagorean ___.
victus00 [196]

A set of 3 nonzero whole numbers say (a,b,c) that form the sides of a right triangle and follow the pythagorous theorem

a^2+b^2=c^2\\

are called a Pythagorean Triple

The example of Pythagorean Triplet are

(3,4,5), (5,12,13) ,(8,15,17), etc.

Hence

A set of 3 nonzero whole numbers that form the sides of a right triangle are called a Pythagorean Triple.

4 0
3 years ago
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