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olya-2409 [2.1K]
3 years ago
13

Laura received a box of chocolates for her birthday. The chocolates in the box have five different fillings. The table below sho

ws how many chocolates with each type of filling are in the box.
The chocolates are all the same shape and size. Laura does not like coconut or toffee. What is the probability that Laura will pick a chocolate from the full box that has a filling she does like?

Probability _______________________

In the space below, explain the process you used to determine your answer

Please help :c somebody!

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
In this question we are asked to find the ratio of the number of chocolates which Lauren liked and the total of chocolates.

We know she doesn't like coconut and toffee, so she likes caramel, mint and cherry. When we count the ones she liked, we got 16+12+14=42.

When we add to find how many chocolates are there, we got 16+10+12+14+8=60.

To find the ratio we need to divide the first one and the second one: \frac{42}{60} = \frac{7}{10} = 0.7 is our probability.
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Recall the formula for the area of a trapezoid, A=1/2h(a+b) , where h is the height and a and b are the lengths of the parallel
Gekata [30.6K]

Answer:

The area of the trapezoid is 40 square inches

Step-by-step explanation:

Here, we want to find the area of the given trapezoid

Mathematically, we apply the formula for the area

In this case, a will be 10, b will be 6 and h will be 5

Substituting these values, we have that ;

A = 1/2(10 + 6)5

A = 1/2(16)(5)

A = 40 square inches

7 0
3 years ago
Read 2 more answers
Bernice estimated that 69% of 242 is 168. Is her estimate reasonable?
ycow [4]
Her estimate is not reasonable.

Since she estimated 69%, you could do either of these options. You could...
A. Divide 242 (or .5) to show how much half off would be, then compare her estimate with half of 242 (121). OR...
B. Simply divide 242 by 69% (.69) and compaor her estimate to the exact amount (166.98).

I hope this helps!
6 0
3 years ago
An urn contains 12 balls, of which 4 are white.
wel

Answer:

a) \frac{1}{3}

b) \frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let A_i\,,\,B_i\,,\,C_i denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: P(A_1)=\frac{4}{12}=\frac{1}{3}

If A lost and B wins: P\left ( B_1|A_1^{c} \right )=\frac{4}{11}

If A and B lost and C wins: P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}

and so on....

4 0
4 years ago
The diagram shows two nested triangles that share a vertex.Find a center and a scale factor for a dilation that would move the l
nasty-shy [4]

Transformation that changes the size of a shape is referred to as dilation.

  • The scale factor that moves the large triangle to the small one is 1/5
  • The center of dilation is: (-1,1)

<u>The center of dilation</u>

From the diagram (see attachment), the triangles share a common vertex at (-1,1)

This means that, the center of dilation is (-1,1)

<u>The scale factor of dilation</u>

To do this, we divide the side length of the small triangle with the corresponding side of the large triangle.

From the attached image:

\mathbf{Base\ of\ small\ triangle = 1}

\mathbf{Base\ of\ large\ triangle = 5}

So, the scale factor (k) from large to small is:

\mathbf{k = \frac{Base\ of\ small\ triangle}{Base\ of\ large\ triangle} }

\mathbf{k = \frac{1}{5} }

Read more about dilation at:

brainly.com/question/13176891

3 0
3 years ago
Help pleaseeeeeeeee​
Doss [256]

Answer:9

Step-by-step explanation: im not really sure I kinda just guess and check, so like, 2/3 times 3 is 6/3 which is 2. so 6/2 is 3. 3 times 3 is nine.

4 0
3 years ago
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