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Mila [183]
3 years ago
10

If yo answered no give an example of 2 outputs that are possible for the same output

Mathematics
1 answer:
dexar [7]3 years ago
3 0
What’s the subject?

20 characters really???
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a rope is stretched from the top of a 7-foot tent pole to point on the ground 12 foot the base of the pole. how long is the rope
bulgar [2K]

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Step-by-step explanation:


6 0
3 years ago
What is the solution to-5x=-75​
Furkat [3]

Answer:

-15

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The Washington, DC, region has one of the fastest-growing foreclosure rates in the nation, as 15,613 homes went into foreclosure
Ilia_Sergeevich [38]

Answer:

a) 0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b) 0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c) The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

Step-by-step explanation:

For each home, there are only two possible outcomes. Either it goes into foreclosure, or it does not. The probability of a home going into foreclosure is independent of other homes. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a. What is the probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure?

The foreclosure rate is 1.31% for the Washington, DC area, which means that p = 0.0131

We wanto to find, with n = 100:

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0131)^{0}.(0.9869)^{100} = 0.2675

P(X = 1) = C_{100,1}.(0.0131)^{1}.(0.9869)^{99} = 0.3551

P(X < 2) = P(X = 0) + P(X = 1) = 0.2675 + 0.3551 = 0.6226

0.6226 = 62.26% probability that in a given year, fewer than 2 out of 100 houses in the Washington, DC area will go up for foreclosure.

b. What is the probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure?

Foreclosure rate of 0.87% for the nation, which means that p = 0.0087. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.0087)^{0}.(0.9913)^{100} = 0.4174

P(X = 1) = C_{100,1}.(0.0087)^{1}.(0.9913)^{99} = 0.3663

P(X < 2) = P(X = 0) + P(X = 1) = 0.4174 + 0.3663 = 0.7837

0.7837 = 78.37% probability that in a given year, fewer than 2 out of 100 houses in the nation will go up for foreclosure.

c. Comment on the above findings.

The proportion of foreclosures in the Nation is lower than in Washington, which means that with a sample size of 100, it is likely to have a small number(fewer than 2) of foreclosures than Washington DC.

7 0
3 years ago
Two trains leave the station at the same time one heading east and one heading west the eastbound train travels 80 miles per hou
k0ka [10]
100*2.2=220
80*2=176
220+176=396

So the two trains will take 2.2 hours so that they are 396 miles apart.
5 0
3 years ago
How do you solve 5(N+4)/3 = N-8
Dmitriy789 [7]

Answer:

n=-22

Step-by-step explanation:

rewrite the equation as <u>5(n+4)</u><u> </u>= n-8

3

now distribute the 5 through the parentheses <u>5n</u><u>+</u><u>2</u><u>0</u><u> </u>= n-8

3

multiply each side by 3 5n+20=3n - 24

subrtact 3n from both sides 5n+20=3n - 24

-3n -3n

2n+20=-24

then subtract 20 from each side 2n +20=-24

-20 -20

Giving you 2n=-44 then divide both sides by 2

<u>2n</u>=<u>-44</u><u> </u>Giving you n=-22

2 2

7 0
2 years ago
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