Answer:
a) 
And replacing we got:

b) 
And then the expected value would be:

Step-by-step explanation:
We assume the following distribution given:
Y 0 1 2 3
P(Y) 0.60 0.25 0.10 0.05
Part a
We can find the expected value with this formula:

And replacing we got:

Part b
If we want to find the expected value of
we need to find the expected value of Y^2 and we have:

And replacing we got:

And then the expected value would be:

Answer:
1-59m
Step-by-step explanation:
Answer: 4.01% interest rate
This value is approximate. It is rounded to the nearest hundredth of a percent.
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Work Shown:
A = P*e^(r*t)
1833 = 1500*e^(r*5)
1833/1500 = e^(5r)
1.222 = e^(5r)
e^(5r) = 1.222
5r = Ln(1.222)
5r = 0.2004888607494
r = 0.2004888607494/5
r = 0.04009777214989
r = 0.0401
r = 4.01%
Answer:
C.0
Step-by-step explanation:
THINK PEMDAS
1*6 multiply first. 1*6 is 6
2*-3 is -6
then when you add them, they cancel out
6-6=0
Answer:
9 C at midday
Step-by-step explanation: