What is the equation of line parallel to y = 3x + 5 and through the point (1, 7)?
Many students are more comfortable using <span>slope intercept form </span>but this kind of problem is actually much easier , using point slope form (which is right below this work)
Step 1
Substitute the slope from original line (3 in this case) into the equation of the line <span>y = 3x + b</span>
Step 2
Substitute the given point (1,7) into the x and y values 7 = 3(1) + b
Step 3
Solve for b (the y-intercept)
Step 4
Substitute this value for 'b' in the slope intercept form equation y = 3x + 4
Method 2: Using Post Slope Form
What is the equation of line parallel to y = 3x + 5 and through the point (1, 7)?
If you're comfortable with point slope form , this is the way to go! Just look how little work there is to do! In fact, all that you have to do is substitute twice!
Step 1
Substitute the slope from original line (3 in this case) into the point slope equation <span>y − y1 = m(x − x1)
y − y1 = 3(x − x1)</span>
Step 2
Substitute the given point (1,7) into the x1 and y1 values <span>y − 7= 3(x − 1)</span>
<span>Practice Problems</span>Problem 1 - Method 1
What is the equation of line parallel to y = 4x + 3 and through the point (5,9)?
