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earnstyle [38]
2 years ago
10

What is 1/4 : 3/4 :: 75 : =

Mathematics
1 answer:
Kitty [74]2 years ago
8 0

Answer:

75 : 225

Step-by-step explanation:

\frac{\frac{1}{4} }{\frac{3}{4} } :\frac{75}{y}

0.25 × y = 0.75 × 75

0.25y = 56.25

0.25y ÷ 0.25 = 56.25 ÷ 0.25

y = 225

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A security guard uses 20 minutes of every hour to walk outside the school, leaving the remaining
Troyanec [42]

Answer:

40/20, 40:20, 40 to 20

Step-by-step explanation:

20min/1hr

40min/1hr

Question order asks ratio from outside time to inside time so the 40 would come first. also, all the above are correct. You can write a ratio as a fraction, with a colon, or with the word to.

6 0
3 years ago
HELP PLEASE!Write the equation of the line parallel to y = –x + 5 passing through the point (9, –1).
Westkost [7]
Y=-x+8
gradient of the parallel line is the same as the gradient of the line given, which is -1
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3 years ago
Which set of ordered pairs does NOT represent a function?
Elina [12.6K]
B is the answer to your question
4 0
3 years ago
Read 2 more answers
How do I complete these questions a bit confused . (extra credit work )​
otez555 [7]

Answer:

(1)

a = \frac{3\sqrt 3}{2}

b = \frac{3}{2}

(2)

a = \sqrt 6

b = \sqrt 2

Step-by-step explanation:

Solving (1):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{3}

Solve for a

a = 3 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 3 * \frac{\sqrt 3}{2}

a = \frac{3\sqrt 3}{2}

To solve for b, we make use of Pythagoras theorem

3^2 = a^2 + b^2

This gives

3^2 = (\frac{3\sqrt 3}{2})^2 + b^2

9 = \frac{9*3}{4} + b^2

9 = \frac{27}{4} + b^2

Collect like terms

b^2 = 9 - \frac{27}{4}

Take LCM and solve

b^2 = \frac{36 - 27}{4}

b^2 = \frac{9}{4}

Take square roots

b = \frac{3}{2}

Solving (2):

Considering

\theta = 60^o

We have:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60^o) = \frac{a}{2\sqrt 2}

Solve for a

a = 2\sqrt 2 * \sin(60^o)

\sin(60^o) = \frac{\sqrt 3}{2}

So:

a = 2\sqrt 2 * \frac{\sqrt 3}{2}

a = \sqrt 2 * \sqrt 3

a = \sqrt 6

To solve for b, we make use of Pythagoras theorem

(2\sqrt 2)^2 = a^2 + b^2

This gives

(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2

8 = 6 + b^2

Collect like terms

b^2 = 8 - 6

b^2 = 2

Take square roots

b = \sqrt 2

3 0
3 years ago
PLEASE HELP i have no clue what the answer is
Nat2105 [25]

Answer:

y=2/3x+19/3

Step-by-step explanation:

Use this equation y-y1=m(x-x1) and plug the numbers in

5 0
2 years ago
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