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barxatty [35]
3 years ago
12

Henry is paid $11.25 an hour at his job before he pays taxes. However, 28% is subtracted from his wages earned for taxes. How ma

ny hours will henry have to work in order to earn $324, after his taxes are deducted?
Mathematics
2 answers:
e-lub [12.9K]3 years ago
6 0
The answer is 40 HOURS. Hope this helps!
skad [1K]3 years ago
5 0
I took 11.25x40=450x28%=324
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For A brainlist ** explain
IrinaVladis [17]

Answer:

So interval notation is with ( and [ where ( is exclusive and [ is inclusive.

Like (1,2) is between 1 and 2 exclusive. [1,2] is between 1 and 2 inclusive. (1,2] is between 1 and 2, 1 exclusive 2 inclusive.

at the point (6,0) you see that the graph goes from above 0 to below 0 (from positive to negative)

The values are positive when x is less than 6 and negative when x is greater than 6.

so the positive interval is

(-infinity, 6)

and with inifinity you always use exclusive

It's that because everything from all the way to the left (-infinity) to 6, is above the x-axis, which means it's positive

using this logic can you do the negative interval?

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3 years ago
2 2/5 x 4 = {Khan Academy}
Sophie [7]

Answer:

9.6 or 9 and 3/5

Step-by-step explanation:

turn 2 and 2 fifths into an improper fraction and multiply by four

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3 years ago
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Lelechka [254]

Answer:

x = -3/2

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7⁰ = 1 (anything to the power of 0 equals 1)

7²ˣ ⁺ ³ = 7⁰

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2x + 3 = 0

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7 0
3 years ago
Suppose that f : [a, b] → [a, b] is continuous. Prove that f has a fixed point. That is, prove that there exists c ∈ [a, b] such
nikklg [1K]

Answer:

Step-by-step explanation:

define the function:

g(x) = f(x) -x

As both f(x) and x are continuous functions, g(x) will also be continuous.

Now, what can we say about g(a) = f(a) -a?

we know that a\leq f(a) \leq b, thus:

a-a\leq f(a)-a \leq b-a\\0 \leq g(a) \leq b-a

thus  g(a) is non-negative.

What about g(b) ? Again we have:

a\leq f(b) \leq b\\a-b \leq f(b) -b \leq  0\\a-b \leq g(b) \leq  0

That means that g(b) is not positive.

Now, we can imagine two cases, either one of g(a) or g(b) is equal to zero, or none of them is. If either of them is equal to zero, we have found a fixed point! In fact, any point c for which g(c)=0 is a fixed point, because:

g(c) = 0 \implies f(c) -c = 0 \implies f(c) = c

Now, if g(a) \neq  0 and g(b) \neq 0, then we have that

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the answer is l*w= A so that is the answer

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3 years ago
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