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3 years ago

There are 450 children in a school, to the nearest 10. How many children could there be ?

Mathematics

2 answers:

Ludmilka [50]3 years ago

8 0

Answer: 450- the answer is already rounded.

Naily [24]3 years ago

3 0

Answer:

Anywhere from 446 to 454 children.

446 rounded to nearest ten is 450.

447 rounded to nearest ten is 450.

448 rounded to nearest ten is 450.

449 rounded to nearest ten is 450.

450 rounded to nearest ten is 450.

451 rounded to nearest ten is 450.

452 rounded to nearest ten is 450.

453 rounded to nearest ten is 450.

454 rounded to nearest ten is 450.

So the answer is 446 - 454 children. Hope it helps!

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4 years ago

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5,000 ones equal to how many thousands

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4 years ago

Which is not an equation of the line going through (6,7) and (2,-1) A. y-7=2(x-6) B. y=2x-5 C. y-1=2(x+2) D. y+1=2(x-2)

nikdorinn [45]

Answer:

C. y-1=2(x+2)

Step-by-step explanation:

A. y-7=2(x-6)-point slope form: y-y1=2(x-x1)-coordinate point: (x1,y1)=(6,7)

Now let's check that the other point works-just sub in the coordinates for the x and y variables.

y-7=2(x-6)\\-1-7=2(2-6)\\-8=2(-4)\\-8=-8

So answer choice A. goes through both points, so no.

B. y=2x-5-slope-intercept form, so just sub in both sets of coordinates separately to see if they each work.

y=2x-5\\7=2(6)-5\\7=12-5\\7=7\\equal

y=2x-5\\-1=2(2)-5\\-1=4-5\\-1=-1\\equal

Both work, so no.

C. y-1=2(x+2)-point slope form that gives us first coordinate set--(-2,1)

Except that the point is actually (2,-1) not (-2,1). That means that answer choice C is not an equation of the line thaat goes through (6,7) and (2,-1), so yes.

D. Anyway, if we check D--y+1=2(x-2)--coordinate point given: (2,-1), which is correct, so no.

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3 years ago

Which of the following triangles have three sides of different length? A. acute B. scalene C.equilateral D. right

katen-ka-za [31]

Answer:

scalene

hope this helps

have a good day :)

Step-by-step explanation:

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3 years ago

Jai Narayan sells two radio sets for 2288 each.

san4es73 [151]

Answer:

Step-by-step explanation:

S.P of each radio=$ 2288

Total S.P= $2\times 2288=$ $4576

Gain=10%

Lose=10%

C.P= $\frac{S.P\times 100}{100+gain(in\;percent)}$

C.P= $\frac{S.P\times 100}{100-loss(in\;percent)}$

By using the formula

C.P of one radio= $\frac{2288\times 100}{110}=$ $2080

C.P of another radio= $\frac{2288\times 100}{100-10}$ =$2542.2

Total C.P of two radios=2080+2542.2=$4622.2

Total C.P >Total S.P

Loss=S.P-C.P

Loss=4622.2-4576=$46.2

Loss%= $\frac{Loss}{C.P}\times 100$

Loss %= $\frac{46.2}{4622.2}\times 100=$ 1%

Hence, his loss 1%

5 0

3 years ago

There are 450 children in a school, to the nearest 10. How many children could there be ?​

There are 450 children in a school, to the nearest 10. How many children could there be ?