1. Name 4 technologies that have helped America develop into a powerful country.

A bag contains 5 yellow marbles, 7 pink marbles, and 3 purple marbles. Gordon selects a marble without looking.

prisoha [69]

1st you add up all the marbles so we got 15 so the answe will be out of 15 then next we add up nhe number of yellow and purple marbles 5+3= 8 so the answe will be 8/15

8 0

3 years ago

A health study tracked a group of person for five years. At the beginning of the study, 20% were classified as heavy smokers, 30

Aleks04 [339]

Answer: 0.421

Step-by-step explanation:

Heavy smoker = 20%

Light smoker = 30%

Non smokers = 50%

We can assume that the probability that a non-smoker is going to die in the next 5 years be y.

Since light smokers were twice as likely as nonsmokers to die during the five-year study, the probability will be:

= 2 × y = 2y

Probability for the Heavy smokers will be:= 2 × 2y = 4y

The expected number of people that will die for each in the next 5 years will be:

Non smoker:

= 50% × y

= 0.5 × y

= 0.5y

Light smoker:

= 30% × 2y

= 0.3 × 2y.

= 0.6y

Heavy smoker:

= 20% × 4y.

= 0.2 × 4y

= 0.8y

Total = 0.5y + 0.6y + 0.8y = 1.9y

The probability that the participant was a heavy smoker will be:

= 0.8y/1.9y

= 0.421

3 0

3 years ago

324 soldiers queued up such that the number of queues is equal to the number of soldiers in each queue. find the number of queue

Yanka [14]

I think so answer will be 164.

8 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

Need help on this question too hard :((

andrew-mc [135]

Answer:

2/3

Step-by-step explanation:

Convert the fractions to decimals.

2/3 = 0.666

4/5 = 0.8

14/18 = 0.777

34/50 = 0.68

From the decimals, 0.666 is the only option which falls between 0.5 and 0.75.

5 0

3 years ago