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marishachu [46]
2 years ago
11

HELP ME PLSSSSSSSSSS

Mathematics
1 answer:
IRINA_888 [86]2 years ago
6 0

Answer:

the last one go to the first one , the first one go to the last one , the secoind go the third one , and the thrid one go to the thrid one sry if i am wrong

Step-by-step explanation:

You might be interested in
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
2 years ago
This is a dumb question but what is 68 time 100
Whitepunk [10]

68 x 100 = 6,800

Hope this helps

-AaronWiseIsBae

3 0
2 years ago
Read 2 more answers
Please help with this question i will mark brainliest!
Blababa [14]

Answer:

hi im going to work on this i wiil comment answer in a minute

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find the product 1/2x3/4.
Sauron [17]

Answer:

The product is 3/8

Step-by-step explanation:

When you multiply two fractions, first multiply the numbers on the top (numerators).

1 * 3 = 3

Then multiply the bottom numbers (denominators).

2 * 4 = 8

Now stick the first over the second.

3/8

7 0
3 years ago
At a certain time of day, the angle of elevation of the sun is 80degree. Find the height of a tree whose shadow is 44 feet long.
Arte-miy333 [17]

The height of the tree is 249.5 feet

<h3>How to determine the height of the tree?</h3>

The given parameters are:

  • Elevation angle = 80 degrees
  • Shadow length (L) = 44 feet

Let the height of the tree be x.

So, we have:

tan(80) = x/44

Multiply both sides by 44

x = 44 * tan(80)

Evaluate

x = 249.5

Hence, the height of the tree is 249.5 feet

Read more about elevation at:

brainly.com/question/19594654

#SPJ1

8 0
2 years ago
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