Answer:
15 ≤ w ≤ 19
Step-by-step explanation:
Given that :
Length of garden = 14 feets
Perimeter must be atleast 58 but no more than 66
The range of value for the width ;
Perimeter = 2 length + 2 width
Perimeter = 2(14) + 2w
If perimeter = 58
58 = 28 + 2w
58 - 28 = 2w
30 /2 = w
w = 15
If perimeter = 66
66 = 28 + 2w
66 - 28 = 2w
38 = 2w
w = 38 / 2
w = 19
Range of the width should be atleast 15 and not more Than 19
Hence,
15 ≤ w ≤ 19
Answer:
1.true
2.false
3.true
Step-by-step explanation:
please give me a brainliest :)
Answer:
1050 g < weight ≤ 1150 g
Step-by-step explanation:
Let w represent the weight of the package in grams. The the number of 100-gram increments after the first 250 grams is given by ...
⌈(w-250)/100⌉ . . . . . . . where ⌈ ⌉ signifies the <em>ceiling</em> function
and the charges for a package exceeding 250 grams will be ...
0.65 + 0.10⌈(w -250)/100⌉ = 1.55
0.10⌈(w -250)/100⌉ = 0.90 . . . . . . . . subtract 0.65
⌈(w -250)/100⌉ = 9 . . . . . . . . . . . . . . . divide by 0.10
8 < (w-250)/100 ≤ 9 . . . . . . . . . . . . . . meaning of ceiling function
800 < w -250 ≤ 900 . . . . . . . . . . . . . multiply by 100
1050 < w ≤ 1150 . . . . . . . . . . . . . . . . . add 250
The weight in grams could be greater than 1050 and at most 1150 for a charge of $1.55.
The factored expression ofx^3 - 7x^2 -5x +35 is (x^2 - 5)(x - 7)
<h3>What is an expression?</h3>
An expression is an algebraic term used for a mathematical statement that includes addition subtraction multiplication and division
x^3 – 7x^2 – 5x + 35
factor the given equation
x^2(x – 7) – 5(x - 7)
Factor out x - 7
(x^2 - 5)(x - 7)
Therefore, the factored expression is (x^2 - 5)(x - 7)
To learn more about the factored expression visit:
brainly.com/question/723406
Answer: Choice ARaising something to the 1/4th power is the same as applying the 4th root to that expression. Raising an expression to the 1/n power is the same as applying the nth root.
Rule:
![x^{1/n} = \sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%7D%20)
(if the text is too small it basically says x to the (1/n) = square root with a small 'n' all over x)