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Furkat [3]
3 years ago
9

What is the slope of the line?

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Hello!

\large\boxed{m = \frac{3}{2}}

\large\boxed{\text{Slope = \frac{3}{2}}}

Use given points and plug them into the slope formula to find the slope of the line:

\text{Slope } = \frac{ y_2 - y_1 } { x_2 - x_1 }

We can use the points (2, -1) and (0, -4) to solve:

\text{Slope } = \frac{ -1 - (-4) } { 2 - 0 }\\\\= \frac{3}{2}

Therefore, the slope, or "m" value of the line is 3 / 2.

nexus9112 [7]3 years ago
3 0

Answer:

it may be steep slop if it is social study

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miv72 [106K]
You should put each question somewhere different so anyone can answer it and see it faster
3 0
4 years ago
Simplify: −7 + {12 − 3[50 − 4(2 + 3) ] }
DedPeter [7]

Answer:

-85

Step-by-step explanation:

<em><u>1) (2 + 3)</u></em>

-7 + {12 - 3[50 - 4(5) ] }

<em><u>2) -7 + {12 - 3[50 - 20] }</u></em>

-7 + {12 - 3[30] }

<em><u>3) -7 + 12 - 90</u></em>

5 - 90

<u>Answer: -85</u>

6 0
4 years ago
Question 17/23
disa [49]

Answer:

60%

Step-by-step explanation:

Formula:

Percentage decrease = (amount of decrease)/(original price)

✪ Solve ✪

3.85 - 1.54/3.85 x 100

2.31/3.85 x 100 = 60%

Hence, Percent decrease is 60%

<em>~Lenvy</em>

6 0
3 years ago
Pls help this should be the last thing
Lelu [443]

Answer:

1436 i believe

Step-by-step explanation:

7 0
3 years ago
Find the equation of the parabola that passes through
valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}

well, from the 1st  equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b

well, now let's plug that "b" into our 3rd equation and solve for "a".

\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill

3 0
3 years ago
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