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kykrilka [37]
3 years ago
14

9. Evaluate (-7) -10 ÷ (-28)-10 pls solve fast

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

17/38 or ≈ 0.45

Step-by-step explanation:

(-7) -10 / (-28)-10

= -17 / -38

= 17/38

You can keep the answer in fraction as 17/38 or ≈ 0.45

Hope this help you :3

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Is 16.263548952347... a rational<br> number and why?
anzhelika [568]

Answer: no it is not

Step-by-step explanation: any number that repeats forever cannot be written as a rational way or a fraction. So it is not rational.

8 0
3 years ago
I need help on this
Mariana [72]

Isolate the w

w/3 = 5

Note the equal sign. What you do to one side, you do to the other.

Multiply 3 to both sides

w/3(3) = 5(3)

w = 5(3)

Multiply

w = 15

15 is your answer for w

hope this helps

5 0
3 years ago
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Ms. Check your answers.
xenn [34]
3kg+2kg=5kg
5/$3.25=0.65
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3 years ago
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Find a cubic function with the given zeros.
Fed [463]

Answer:

The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

Substitute x=-√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0

Therefore, the option is correct.

8 0
3 years ago
Which of the following is a rational number? square root of 36, square root of 37, square root of 38, square root of 39 square r
Rainbow [258]
The answer is square root of 36
because the square root of 36= 6
whereas the square roots of 37,38 and 39 give you recurring decimals
6 0
3 years ago
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