Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
the answer is A
these are filler words so I can submit it haha
Answer:
Adults $ 17
Students: $8
Step-by-step explanation:
Adults: x
Students: y
a) 25x + 31y = 673
b) 27x +31y = 707
Elimination:
a) -1(25x + 31y = 673) = -25 -31y = -673
a + b
= (-25 -31y = -673) + (27x + 31y = 707)
= 2x = 34
x = 34/2
x = 17
Substitution a or b:
a) 25(17) + 31y = 673
425 + 31y = 673
31y = 673 - 425
31y = 248
y = 248/31
y = 8
Answer:
![y=-\frac{2}{3}x-3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B2%7D%7B3%7Dx-3)
Step-by-step explanation:
To write the equation of a line we need 2 points. We know:
- If the y-intercept of the line is -3 then the point is (0,-3).
- If the x-intercept of the line is -4.5 then the point is (-4.5,0).
Using these two point, we will find the slope and then substitute it into the point slope form
with a point.
Slope: ![m=\frac{0--3}{-4.5-0}=\frac{0+3}{-4.5}=\frac{3}{-4.5}=-0.6667](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0--3%7D%7B-4.5-0%7D%3D%5Cfrac%7B0%2B3%7D%7B-4.5%7D%3D%5Cfrac%7B3%7D%7B-4.5%7D%3D-0.6667)
This decimal is -2/3. We will now substitute -2/3 and (0,-3) into the point slope form.
![y--3=-\frac{2}{3}(x-0)\\y+3=-\frac{2}{3}(x)\\y+3=-\frac{2}{3}x\\y=-\frac{2}{3}x-3](https://tex.z-dn.net/?f=y--3%3D-%5Cfrac%7B2%7D%7B3%7D%28x-0%29%5C%5Cy%2B3%3D-%5Cfrac%7B2%7D%7B3%7D%28x%29%5C%5Cy%2B3%3D-%5Cfrac%7B2%7D%7B3%7Dx%5C%5Cy%3D-%5Cfrac%7B2%7D%7B3%7Dx-3)