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FrozenT [24]
3 years ago
12

Need help with problem 40,41 and 42! 15 points

Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0

Answer:

40) w = 32/3

41) x = 23/4

42) w = 1/12

Step-by-step explanation:

40) Real world problem:

If Lisa takes $ 7\frac{3}{8} $ of the pie from a total of $w$ slices, then the remaining pie is $ 3 \frac{7}{24} $. Find w.

So, the equation would become:

$ w - 7 \frac{3}{8} = 3 \frac{7}{24} $

$ \implies w = 3 \frac{7}{24} + 7 \frac{3}{8} $

This can be written as:

$ w = 3 + \frac{7}{24} + 7 + \frac{3}{8} $

This is equivalent to $ 3 + \frac{7}{24} + 7 + \frac{9}{24} $

Since, the denominator is the same, the numerators can be added now.

$ \implies  w = 10 + \frac{16}{24} $

$ \implies w = 10 + \frac{2}{3} $

$ i.e., w = 10 \frac{2}{3} = \frac{32}{3} $

Hence, the answer is 32/3.

41) The given equation is: $ 2 \frac{1}{2} + x = 8\frac{1}{4} $

$ 2 \frac{1}{2} = \frac{5}{2} $ and

$ 8 \frac{1}{4} = \frac{33}{4} $

So, $ x = \frac{33}{4} - \frac{10}{4} $

$ \implies x = \frac{23}{4} $

The answer is 23/4.

42) The given equation is $ w - \frac{1}{3}  = \frac{5}{12}

$ \implies w = \frac{5}{12} - \frac{1}{3} $

$ w = \frac{5}{12} - \frac{4}{12} $

$ w = \frac{1}{12} $

The answer is 1/12.

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Answer: 27.42 ft

Step-by-step explanation:

To find the perimeter first we must find the circumference of the circles.

You can easily find the diameter by subtracting and you get 6.

Using the circle circumference formula c=2piR you get 9.42.

9.42 is our circumference of one circle.

You don't need to divide this by 2 because you already have 2 halves of a circle.

Next add all the sides which is 18.

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Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

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And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

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