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maks197457 [2]
3 years ago
7

Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts

were $2,771. How many adult tickets and how many child tickets were sold?
Mathematics
1 answer:
elixir [45]3 years ago
8 0

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

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