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bogdanovich [222]
3 years ago
14

How many prime numbers are there between zero and 25

Mathematics
2 answers:
creativ13 [48]3 years ago
6 0

Answer:

2, 3, 5, 7, 11, 13, 17, 19, 23

so there are 9.

Hope This Helps!   Have A Nice Day!!

IgorC [24]3 years ago
3 0

I believe there are ten. One, two, three, five, seven, eleven, thirteen, seventeen, nineteen, and twenty-three.

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2(5x + 7) = 34<br><br> Someone help me
Pepsi [2]

Answer:

x = 2

Step-by-step explanation:

2(5x + 7) = 34

10x + 14 = 34

10x = 34 - 14

10x = 20

x = 20/10

x = 2

7 0
4 years ago
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I need help on this!
marshall27 [118]
That is a 45 45 90 triangle.
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3 years ago
Solve for x <br> •26.45 <br> •10.93<br> •14.26<br> •22.19 <br> •20.26
ollegr [7]

Answer:

x = 26.45

Step-by-step explanation:

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3 years ago
Factorization for the monomial<br> <img src="https://tex.z-dn.net/?f=48x%5E%7B10%7D" id="TexFormula1" title="48x^{10}" alt="48x^
Schach [20]

Answer:

Some of the possible factorizations of the monomial given are:

(16x^5)(3x^5)

(48x)(x^9)\\\\(4x^5)(12x^5)\\\\(16x^2)(3x^8)\\\\(2x^2)(4x^7)(6x)

Step-by-step explanation:

 To factorize the monomia you need to express it as a product of two or more monomials.  Therefore, you must apply the proccedure shown below:

- Descompose into prime numbers:

48x^{10}=2*2*2*2*3*x*x*x*x*x*x*x*x*x*x

- Then, keeping on mind that, according to the Product of powers property, when you have two powers with equal base you must add the exponents, you can make several factorizations.  Below are shown some of the possible factorizations of the monomial given:

(2^4x^5)(3x^5)

(48x)(x^9)\\\\(4x^5)(12x^5)\\\\(16x^2)(3x^8)\\\\(2x^2)(4x^7)(6x)

3 0
3 years ago
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iVinArrow [24]
The answer is B (-2,2)
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