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Aneli [31]
3 years ago
15

The 2007 record for the University of North Carolina softball team was 46 wins to 21

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

the ratio is still 46:21 because it cn't be reduced any further

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A.) When you move to the left on a number line, the movement is positive or negative?
fredd [130]

Answer:

a)negitive b)positive

Step-by-step explanation:

to the left of zero on a number line is negitive numbers and to the right is positive

4 0
3 years ago
Read 2 more answers
I couldn't figure this one out​
NARA [144]

Answer:

59˚

Step-by-step explanation:

The sum of all the angles in a triangle is always 180 so:

38 + 83 + x = 180

121 + x = 180

x = 59

4 0
3 years ago
What are the intercepts of y = 4x − 2?
maw [93]

Answer: y = −2

Step-by-step explanation:

  • 0 = −4x − 2
  • x = −1/2
  • To find the y-intercept, substitute in 0 for x and solve for y. Y = − 4 * 0 −2
  • Which then gives you y = - 2

* Hopefully this helps:) Mark me the brainliest:)

4 0
3 years ago
Rewrite each equation in slope-intercept form, if necessary. Then determine whether the lines are parallel. Explain,
Oksana_A [137]
Answer:
d

Step-by-step explanation:

Slope intercept form: y = mx + b

y = -x + 7
x + y = 21

x + y = 21
-x -x
y = -x + 21


y = -x + 7
y = -x + 21

Parallel lines have the same slope. Here, our slope is -1

Therefore, our final answer is d.


Hope this helps!
8 0
2 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
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