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stealth61 [152]
3 years ago
14

What are all of the energy transformations that take place as sunlight is converted to usable energy within humans

Biology
1 answer:
Charra [1.4K]3 years ago
4 0
<span>The energy transformation in the sun is primarily the change of nuclear energy to light energy. 

More Explainable: </span><span>The sun is said to "burn hydrogen" but what that really means is that near the center of the sun there is enough temperature and pressure to cause the fusion of hydrogen nuclei (protons) into helium nuclei (two protons and two neutrons). The fusion (not fission) reaction energy give off energy in a complex way that includes heat and light. The light works its way out from the center of the sun to the surface and eventually out of the surface into space. That is the sunlight we see as well as some light that is outside our range of vision. The light is electromagnetic energy. </span>
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The answer u r looking for is- B, The electron transport chain stops, stopping the citric acid cycle. Hope I’ve helped ;)
5 0
3 years ago
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Why doesn't our hands swell up due to osmosis , when we keep it in water for a long time ??
DerKrebs [107]
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In short, plant cells have cell walls that allow osmosis while animal cells do not have cell walls for osmosis to take place

hope it helps you :)

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8 0
3 years ago
When a molecule moves through the cell membrane by facilitated diffusion, what must it move through?​
aalyn [17]
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3 0
2 years ago
A 35 kg child moves with uniform circular motion while riding a horse on a carousel. The horse is 3.2 m from the carousel's axis
Andrews [41]
<h2>Hello!</h2>

The answer is:

b. \frac{2.11m}{s^{2}}

<h2>Why?</h2>

The centripetal acceleration or radial acceleration is present when an object is moving to describe a circular path. The centripetal acceleration is always perpendicular to the direction of the velocity and going inwards and towards the center.

The centripetal acceleration can be calculated using the following equation:

CentripetalAcceleration=\frac{v^{2}}{RadiusOfMotion}

From the statement we know that:

v=TangentialSpeed=\frac{2.6m}{s} \\R=3.2m

So, calculating we have:

CentripetalAcceleration=\frac{{2.6^{2} \frac{m}{s} }}{3.2m}=\frac{{6.76\frac{m}{s} }}{3.2m}=\frac{2.11m}{s^{2} }

So, the correct answer is:

b. \frac{2.11m}{s^{2}}

Have a nice day!

8 0
3 years ago
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