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Romashka [77]
3 years ago
7

Find the zeroes and give the multiplicity.

D" id="TexFormula1" title="f(x)=4x^{4}+8x^{3}+4x^{2}" alt="f(x)=4x^{4}+8x^{3}+4x^{2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Amanda [17]3 years ago
4 0
The answer would be 4x^2(x+1)^2. You first divide by the greatest common factor which is 4x^2. This would leave you with 4x^2(x^2 + 2x + 1). After that, you would factor it out to find the zeroes. You can multiply 1 x 1 to get one and add 1 + 1 to get two. Therefore, you would get 4x^2(x+1)(x+1). However, there are two ones so you can just square it. This would leave you with your final answer of 4x^2(x+1)^2.
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3 years ago
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Charra [1.4K]

Answer:

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Step-by-step explanation:

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The first 3-digit prime is 101, so the product of that with this is ...

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  7(7⁴ +4) = 7(1 +4) = 5 . . . . mod 10

  9(9⁴ +4) = 9(1 +4) = 5 . . . . mod 10

In every case, the units digit of 101z will be 5.

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2 years ago
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