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Romashka [77]
2 years ago
7

Find the zeroes and give the multiplicity.

D" id="TexFormula1" title="f(x)=4x^{4}+8x^{3}+4x^{2}" alt="f(x)=4x^{4}+8x^{3}+4x^{2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Amanda [17]2 years ago
4 0
The answer would be 4x^2(x+1)^2. You first divide by the greatest common factor which is 4x^2. This would leave you with 4x^2(x^2 + 2x + 1). After that, you would factor it out to find the zeroes. You can multiply 1 x 1 to get one and add 1 + 1 to get two. Therefore, you would get 4x^2(x+1)(x+1). However, there are two ones so you can just square it. This would leave you with your final answer of 4x^2(x+1)^2.
You might be interested in
4/5 + 5/6 + 7/2 equals what
Zanzabum
Equal to 5.13333...
Or 77/15
3 0
2 years ago
At barlow school 4/9 of the 873 students are boys at willow school 2/3 of the 630 students are girls which school has the greate
marishachu [46]

Answer:

There are 178 more boys in Barlow school as compared to Willow school.

Step-by-step explanation:

We are given the following in the question:

Barlow school:

Total number of students = 873

Number of boys =

=\dfrac{4}{9}\times 873 = 388

Willow school:

Total number of students = 630

Number of girls =

=\dfrac{2}{3}\times 630 = 420

Number of boys =

Total number of students - total number of girls

=630-420 = 210

Thus, Barlow school has greater number of boys than Willow school.

Difference between the number of boys =

=388-210\\=178

Thus, there are 178 more boys in Barlow school as compared to Willow school.

7 0
3 years ago
(8n^2+4n^4)+(7n^3-4n^4)
Lina20 [59]

Answer:

8n^2+7n^3

Step-by-step explanation:

8n^2+4n^4+7n^3-4n^4

=8n^2+7n^3

4 0
3 years ago
Express the complex number in trigonometric form -6 + 6sqrt3i
marusya05 [52]
\large\begin{array}{l}\\\\ \textsf{This is a complex number in }\mathsf{a+bi}\textsf{ form:}\\\\ \mathsf{z=-6+6\sqrt{3}\,i}\\\\ \textsf{where }\mathsf{a=-6~~and~~b=6\sqrt{3}.} \end{array}


\large\begin{array}{l}\\\\ \bullet~~\textsf{1}\mathsf{^{st}}\textsf{ step: Find the absolute value of z (complex modulus of z):}\\\\ \mathsf{|z|=\sqrt{a^2+b^2}}\\\\ \mathsf{|z|=\sqrt{(-6)^2+(6\sqrt{3})^2}}\\\\ \mathsf{|z|=\sqrt{36+36\cdot 3}}\\\\ \mathsf{|z|=\sqrt{36\cdot 108}}\\\\ \mathsf{|z|=\sqrt{144}}\\\\ \mathsf{|z|=12} \end{array}


\large\begin{array}{l}\bullet~~\textsf{2}\mathsf{^{nd}}\textsf{ step: Find the argument }\mathsf{\theta}\textsf{ of z:}\\\\ \mathsf{arg(z)=\theta}\\\\ \textsf{is an angle that satisfies the following conditions:}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{a}{|z|}=\dfrac{a}{\sqrt{a^2+b^2}}}\\\\ \mathsf{sin\,\theta=\dfrac{b}{|z|}=\dfrac{b}{\sqrt{a^2+b^2}}} \end{cases}\qquad\quad-\pi


\large\begin{array}{l}\textsf{For }\mathsf{z=-6+6\sqrt{3}\,i,}\\\\ \begin{cases} \mathsf{cos\,\theta=\dfrac{-6}{12}=-\,\dfrac{1}{2}}\\\\ \mathsf{sin\,\theta=\dfrac{6\sqrt{3}}{12}=\dfrac{\sqrt{3}}{2}} \end{cases}\\\\\\ \textsf{Since}\\\\ \mathsf{cos\,\theta0,}\\\\ \theta\textsf{ lies in the 2}\mathsf{^{nd}}\textsf{ quadrant.}\\\\\\\textsf{Therefore,}\\\\ \mathsf{\theta=\dfrac{2\pi}{3}~rad~~(120^\circ)} \end{array}


\large\begin{array}{l}\bullet~~\textsf{3}\mathsf{^{rd}}\textsf{ step: Express z in the trigonometric form:}\\\\ \begin{array}{rcl} \mathsf{z}&\!\!=\!\!&\mathsf{|z|\cdot (cos\,\theta+i\,sin\,\theta)}\\\\ \mathsf{-6+6\sqrt{3}\,i}&\!\!=\!\!&\mathsf{12\cdot \left(cos\, \dfrac{2\pi}{3}+i\,sin\,\dfrac{2\pi}{3}\right)\qquad\quad\checkmark} \end{array} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2154167


\large\textsf{I hope it helps.}


Tags: <em>complex number trigonometric form trig absolute value modulus argument angle</em>

4 0
3 years ago
Tommy earns $7.50 per hour when he works at his neighborhood pet store. How much money does Tommy earn by working 4 hours
nalin [4]

Answer:


Step-by-step explanation:


heyaaa,

<u><em>He earns:($7.50 per hour) x (4 hours) = $30</em></u>

thanx mark as brainlest.


3 0
2 years ago
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