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Elodia [21]
3 years ago
9

A key code must contain 6 numerals. There are 10 numerals available. Using these numerals, how many different key codes may be c

reated?
Mathematics
1 answer:
sattari [20]3 years ago
4 0
Imagine tha the each numeral of the code is written over each line:

__  __  __  __  __  __
1      2    3    4    5   6

Every position may have any of the 10 different numerals.

So over the first line you can put 10 different numerals and the same is true for each of the six positions.

So you can create 10x10x10x10x10x10 = 1,000,000 different codes.
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Which of the following is two-dimensional and infinitely large?
Makovka662 [10]

Answer:

D. A solid

Step-by-step explanation:

4 0
3 years ago
Learning Task 3
ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. Distance = 3682km

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. L < 38m

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

Perimeter = 160

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

Perimeter = x + x + 1 + x + 2 + x + 3

This gives:

160 = x + x + 1 + x + 2 + x + 3

Collect Like Terms

160 -1-2-3= x+x+x+x

154= 4x

Divide both sides by 4

38.5 = x

x =38.5

<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>

<em></em>

Solving (b):

Given

Presently: Inzo = 10 + Miz

Five years ago: Miz - 5= \frac{1}{3} * (Inzo-5) --- (Missing from the question)

Required: Determine their present ages

Substitute 10 + Miz for Inzo in the second equation

Miz - 5 = \frac{1}{3} * (10 + Miz - 5)

Miz - 5 = \frac{1}{3} * (Miz + 5)

Multiply both sides by 3

3Miz - 15 = Miz + 5

Collect Like Terms

3Miz -Miz = 15  + 5

2Miz= 20

Divide both sides by 2

Miz = 10

Substitute 10 for Miz in Inzo = 10 + Miz

Inzo = 10 + 5

Inzo = 15

<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>

Solving (3):

Given

Express Train:

Speed = 100kph

Time = t

Local Train:

Speed = 45kph

Time = t + 45

Required: Determine the distance between A and B

Distance is calculated as:

Distance = Speed * Time

For the express train:

Distance = 100 * t

For the local train

Distance = 45 * (45 + t)

Distance between both stations are equal; So,

100 * t = 45 * (45 + t)

100 t = 2025 + 45t

Collect Like Terms

100 t -45t= 2025

55t= 2025

Divide by 55

t = 36.82

Substitute 36.82 for t in Distance = 100 * t

Distance = 100 * 36.82

Distance = 3682km

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: n + n + 2 > 24

Sum less than 60: n + n + 2 < 60

So, we have:

n + n + 2 > 24

2n + 2 > 24

Collect Like Terms

2n > 24-2

2n > 22

n > 11

n + n + 2 < 60

2n + 2< 60

Collect Like Terms

2n < 60-2

2n < 58

Divide by 2

n

So, we have:

n > 11 and n < 29

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

Perimeter < 152m

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

Perimeter =4 * L

Perimeter =4  L

So, we have:

4L < 152m

Divide through by 4

L < 38m

Hence, length is less than 38m (e.g. 37m)

5 0
3 years ago
HELP DUE IN 10 MINS!<br><br> x =??
Black_prince [1.1K]

Answer:

x = 11

Step-by-step explanation:

Using Secants ad Segments Theorem we can say;

(x + 7) (7) = (15 + 6) (6)

7x + 49 = (21) (6)

7x + 49 = 126

7x = 77

x = 11

Hope this helps!

3 0
3 years ago
Read 2 more answers
Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma
Grace [21]

Given that x+y=1, we have y=1-x, so that

f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2

Take the derivative and find the critical points of g:

g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12

Take the second derivative and evaluate it at the critical point:

g''(x)=4>0

Since g'' is positive for all x, the critical point is a minimum.

At the critical point, we get the minimum value g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12.

5 0
3 years ago
The length of a rectangle is equal to triple the width. Write a system of equations can be used to tind the dimensions of the re
PtichkaEL [24]

Answer:

98 = 2w + 2L,

L = 3w

Step-by-step explanation:

Use the perimeter formula:

2) Perimeter = 2w + 2L (where w is the width and L is the length)

Since the length is three times the width we can write:

L = 3w

We can substitue L with 3w:

Perimeter is equal to 98 so,

98 = 2w + 6w = 8w

W = 98/8

Therefore w is 12.25, and L is 36.75

5 0
3 years ago
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