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dangina [55]
2 years ago
12

This figure represents the base of a fish tank that is 8 inches high.

Mathematics
1 answer:
Igoryamba2 years ago
7 0

The volume of the fish tank is 408 in³

To solve the volume of the fish tank, we need to understand what is the volume of plane shapes.

<h3>What is the volume of plane shapes?</h3>

The volume of plane shapes resembles a 3-dimensional space showing the area enclosed by the shape.

From the figure given:

The figure can be differentiated into two shapes;

  • A rectangle
  • A triangle

The volume of the rectangle is known as:

  • = Length × Breadth
  • = 7 inches × 6 inches
  • = 42 inches²

The volume of the triangle is:

  • = 1/2 × base × height
  • = 1/2 × 3 × 6
  • = 9 inches²

The total volume of the base of the fish tank now is:

  • = 42 inches² + 9 inches²
  • = 51 inches²

Now, the volume of the fish tank is:

  • = Height × base of the fish tank
  • = 8 inches × 51 inches²
  • = 408 in³

Learn more about the volume of plane shapes here:

brainly.com/question/20475473

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Step-by-step explanation:

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Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

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\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

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