Hi there!
Our interval is from 0 to 3, with 6 intervals. Thus:
3 ÷ 6 = 0.5, which is our width for each rectangle.
Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:
0.5, 1, 1.5, 2, 2.5, 3
Evaluate:
(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =
Simplify:
0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875
The percentage form of given fraction is 60% and the hundredths form is 0.60
According to the statement
we have given that the a fraction and we have to find the percentage of that fraction and write in the form hundredths.
So, For this purpose,
The given fraction is 12/20.
Then the definition of the percentage is that
The Percentage, a relative value indicating hundredth parts of any quantity.
so, the percentage of given fraction is :
Percentage fraction = 12/20 * 100
After solving it, The percentage fraction will become:
Percentage fraction = 60%
and Now convert into the hundredths form then
In the hundredths form it will become
from 60% to 0.60.
So, The percentage form of given fraction is 60% and the hundredths form is 0.60
Learn more about Percentage here
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Answer:
x = 8^3
Step-by-step explanation:
To rewrite an equation with logs in exponential form, you need to know
logb(a) = m is equivalent to a= b^m
So given log8 (x) = 3 is equivalent to x = 8^3
Answer:
First rectangular solid and second Rectangular solid
1. Bases are in the form of square having same dimensions
2. Height of first rectangular solid=2 ×Height of second rectangular solid
The true statements are
A) The bases are congruent.→The meaning of term congruent is that , the two bases are in the shape of square having same dimensions.
(B) No, The solids are not similar.as ratio of side lengths in not same in each case , because the ratio of heights of two solid is equal to .
(D) Volume of first solid = x *x*2 H=2 x²H
Volume of second solid = x*x*H=x²H
Ratio of volumes =2:1
So, option (D) is true.
(E) Surface area of first solid =2[x*x+x*2 H+2 H*x]
=2[x²+4 H*x]=2 *x*[x+4* H]
Surface area of second solid = 2[x*x+x* H+ H*x]=2[x²+2 H*x]=2* x*[x+ 2*H]
Option A, D, E are correct about two solids.
Step-by-step explanation:
The answer would be B C E hope this helps :)
