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scoundrel [369]
3 years ago
15

Solve the following question. x/10=4 ​

Mathematics
1 answer:
Softa [21]3 years ago
4 0

Answer:

x = 40

Step-by-step explanation:

x/10 = 4

Multiply each side by 10 to isolate x

x/10 *10 = 4*10

x = 40

You might be interested in
Dan drives 140 miles on Monday and 125 km on Tuesday. How many km did he drive in total?
pogonyaev

Answer:

365.308 km

Explanation:

If you convert 140 miles into kilometers you get 225.308 km. Then you just have to add 140 and 225.308 together to get your answer. Hope this helped.

6 0
3 years ago
Find the exact value of the trigonometric expression.
Dmitrij [34]
\bf \textit{Half-Angle Identities}
\\\\
sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}}
\qquad 
cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}\\\\
-------------------------------\\\\
\cfrac{1}{12}\cdot 2\implies \cfrac{1}{6}\qquad therefore\qquad \cfrac{\pi }{12}\cdot 2\implies \cfrac{\pi }{6}~thus~ \cfrac{\quad \frac{\pi }{6}\quad }{2}\implies \cfrac{\pi }{12}

\bf sec\left( \frac{\pi }{12} \right)\implies sec\left( \cfrac{\frac{\pi }{6}}{2} \right)\implies \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\impliedby \textit{now, let's do the bottom}
\\\\\\
cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{1+cos\left( \frac{\pi }{6} \right)}{2}}\implies \pm\sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \pm\sqrt{\cfrac{\frac{2+\sqrt{3}}{2}}{2}}

\bf \pm \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \pm\cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\implies \pm \cfrac{\sqrt{2+\sqrt{3}}}{2}
\\\\\\
therefore\qquad \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\implies \cfrac{2}{\sqrt{2+\sqrt{3}}}


which simplifies thus far to 

\bf \cfrac{2}{\sqrt{2+\sqrt{3}}}\cdot \cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\cdot \stackrel{conjugate}{\cfrac{2-\sqrt{3}}{2-\sqrt{3}}}
\\\\\\
\cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{2^2-(\sqrt{3})^2}\implies \cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{1}

\bf 2\sqrt{2+\sqrt{3}}(2-\sqrt{3})\impliedby \stackrel{\textit{keep in mind that}}{(2-\sqrt{3})=(\sqrt{2-\sqrt{3}})(\sqrt{2-\sqrt{3}})}
\\\\\\
2\sqrt{2+\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}
\\\\\\
2\sqrt{(2+\sqrt{3})(2-\sqrt{3})\cdot (2-\sqrt{3})}
\\\\\\
2\sqrt{[2^2-(\sqrt{3})^2]\cdot (2-\sqrt{3})}\implies 2\sqrt{1(2-\sqrt{3})}
\\\\\\
2\sqrt{2-\sqrt{3}}
7 0
4 years ago
Schweser Satellites Inc. produces satellite earth stations that sell for $115,000 each. The firm's fixed costs, F, are $3 millio
ExtremeBDS [4]

The incremental profit is $175,000 and the new situation would obviously have less business risk than the old one.

<h3>Incremental profit</h3>

First step

Profit $600,000

Add Fixed cost $3,000,000

Contribution $3,600,000

Variable Cost=Total Sales−Contribution

Variable Cost=$115,000×50-$3,600,000

Variable Cost=$2,150,000

Second step

Profit at revised cost

Sales $8,625,000

(75x $115,000)

Less: Variable cost $4,350,000

[75×($3,000,000+$500,000/50-$12,000)]

Contribution $4,275,000

Less Fixed cost $3,500,000

($3,000,000+$500,000)

Profit $775,000

Incremental profit=Profit at revised cost-Existing profit

Incremental profit=$775,000-$600,000

Incremental profit=$175,000

Expected rate of return=Incremental profit/Investment

Expected rate of return=$175,000/$4,000,000×100

Expected rate of return=$4.375%

2. Break-even point

Existing

Break-even point=Fixed cost/Contribution

Break-even point=$3,000,000/[($115,000-($3,000,000+$500,000/50)]

Break-even point=$3,000,000/[($115,000-$70,000)

Break-even point= 66.67

Revised

Break-even point=Fixed cost/Contribution

Break-even point=$3,500,000/[($110,000-($3,000,000/50)]

Break-even point=$3,000,000/[($110,000-$60,000)

Break-even point=60

II. The new situation would obviously have less business risk than the old one.

Learn more about incremental profit here:

brainly.com/question/15968520

#SPJ1

7 0
2 years ago
Can anyone help me??
yulyashka [42]
The answer to your question is D because it is a trinomial

I think
hope this helps
4 0
3 years ago
jenny charges $9.15 an hour to babysit toddlers and $7.45 an hour to babysit school-aged children, if jenny babysat toddlers for
choli [55]

The total money earned by Jenny is \boxed{\bf \$\ 127.05}.

Further explanation

Multiplication is a arithmetic operation such that two real numbers are performed in such a way that they derive a third number called product.

Procedure used:

The following steps are involved to find the value of y\text{ unit} where y is any real number.

1) If one unit is equal to x then multiply y with x.

2) The resultant number would be xy is the value of y\text{ unit}.

Given:

Jenny charges \$\ 9.15 an hour to babysit toddlers and \$\ 7.45 an hour to babysit school-aged children. She babysat toddlers for 9\text{ hours} and school aged children for 6\text{ hours}.

Calculation:

Step 1: Jenny earns through babysit toddlers.

If jenny charges \$\ 9.15 an hour to babysit toddlers and she does this job for 9\text{ hours}.

The earning money from babysit toddlers using above procedure can be calculated as follows:

\begin{aligned}a&=9.15\cdot 9\\&=82.35\end{aligned}

Therefore, jenny earns \$\ 82.35 by babysit toddlers.

Step 2: Jenny earns through school aged children.

If jenny charges \$\ 7.45 an hour to babysit school aged children and she does this job for 6\text{ hours}.

The earning money from babysit school aged children using above procedure can be calculated as follows:

\begin{aligned}b&=7.45\cdot 6\\&=44.7\end{aligned}  

Therefore, Jenny earns \$\ 44.7 by babysit school aged children.

Step 3: Total amount earn by Jenny.

The total earning is the sum of earning through babysit toddlers and babysit school aged children.

The total earning is calculated as follows:

\begin{aligned}\text{Total money}&=82.35+44.7\\&=127.05\end{aligned}

Thus, total money earned by jenny is \boxed{\bf \$\ 127.05}.

Learn more

1. Problem on the whole numbers are positive integers brainly.com/question/1852063.

2. Problem on the adding and simplifying the numbers brainly.com/question/894273.

3. Problem on the general form of the equation of the circle brainly.com/question/1506955.

Answer details:

Grade: Junior school

Subject: Mathematics

Chapter: Multiplication

Keywords: Jenny, babysit, toddlers, school aged children, hour, multiplication, addition, total earning, real numbers, unit, sum, operation, money.

5 0
3 years ago
Read 2 more answers
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