All categories

2 years ago

Can someone help me with this math work my brain broke-

Mathematics

1 answer:

marta [7]2 years ago

8 0

Answer:

1. 90

2.60

3.30

4. 40

5. 80

6. 60

7. 30

8. 30

9. 120

Total for all triangles=180

Step-by-step explanation:

In all the problems, you have to solve for y. This can be done because the three angles are supplementary For example, in the first diagram, you have:

3y+2y+y=180

6y=180

y=30

It's fairly easy to solve from there. Just more multiplying and subtracting.

You might be interested in

I need help with 1 & 2 tyvm

BabaBlast [244]

Answer:

1. x=17.5

2. x=77

Step-by-step explanation:

1. -x=-3x+35

=2x=35

x=17.5

2. -x/7+8=-3

=-x/7=-11

=-x=-77

x=77

5 0

2 years ago

Read 2 more answers

What is the radius for the circle given by the equation?

alisha [4.7K]

Use:

$(a-b)^2=a^2-2ab+b^2\qquad(*)$

$x^2+y^2-6y-12=0\ \ \ \ |+12\\\\x^2+y^2-6y=12\\\\x^2+y^2-2y\cdot3=12\ \ \ \ |+3^2\\\\x^2+\underbrace{y^2-2\cdot y\cdot3+3^2}_{(*)}=12+3^2\\\\x^2+(y-3)^2=21\\\\\boxed{k=3}$

7 0

3 years ago

Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]

True [87]

Answer:

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Step-by-step explanation:

The inverse of a square matrix $A$ is $A^{-1}$ such that

$A A^{-1}=I$ where I is the identity matrix.

Consider, $A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]$

$\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}$

$\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0$

$\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}$