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Klio2033 [76]
2 years ago
9

Explain why 0.07=0.070

Mathematics
1 answer:
beks73 [17]2 years ago
7 0
Because there is no change. 
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Hi<br><br> 1-5 already done!!!!!!!!!!
Scilla [17]

Answer:

According to tangents secant segments theorem,

11) x(16+x) = (x + 6)^2

x (16+x) = (x + 6)^2

16x + x^2 = x^2 + 2(6)(x) + 6^2

16x + x^2 = x^2 + 12x + 36

16x - 12x + x^2 - x^2 = 36

4x = 36

x = 36/4

x = 4

13) x(x + 5) = (x + 2)^2

x^2 + 5x = x^2 + 2x 2(2)(x) + 2^2

x^2 + 5x = x^2 + 4x + 4

x^2 -x^2 + 5x - 4x = 4

x = 4

14) x + 8( x + 8 + 32) = (3x) ^2

x + 8(x + 40) = 9x^2

x(x + 8) + 40(x + 8) = 9x^2

x^2 + 8x + 40x + 320 = 9x^2

x^2 + 48x + 320 =9x^2

48x + 320 = 9x^2 - x^2

48x + 320 = 8x^2

Dividing the whole eq. by 8,

6x = 40 = x^2

0 = x^2 - 6x - 40

0 = x^2 - 10x + 4x - 40

0 = x(x - 10) + 4(x - 10)

x - 10 = 0 OR x + 4 = 0

x = 10 OR x = - 4

length cannot be negative, so,

x = 10

15) (x + 3) ( x + 3 + 15) = (2x) ^2

(x + 3) (x + 18) = 4x^2

x(x + 18) + 3(x + 18) = 4x^2

x^2 + 18x + 3x + 54 = 4x^2

x^2 + 21x + 54 = 4x^2

0 = 4x^2 - x^2 - 21x - 54

0 = 3x^2 - 21x - 54

Dividing the whole eq. by 3,

x^2 - 7x - 18 = 0

x^2 - 7x - 18 = 0

x^2 - 9x + 2x - 18 = 0

x(x - 9) + 2 (x - 9)

x + 2 = 0 Or x - 9 = 0

x = -2 or x = 9

length cannot be negative,so,

x = 9

3 0
3 years ago
One eighth of a number is ten less than one third of the number. Find the number.
GarryVolchara [31]
X/8 - 10 = x/3

bring the values with the variable on one side

x/3 - x/8 = 10

find a common denominator and subtract these fractions

8x/24 - 3x/24 = -10

now subtract fractions

8x - 3x = 5x

5x/24 = -10

multiply both sides by 24

5x = -240

divide both sides by 5

x = -48

the number is -48
7 0
3 years ago
Read 2 more answers
What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?
AlladinOne [14]

Answer:

a=-2\\b=4\\c=-3

Step-by-step explanation:

In a quadratic equation in the Standard form

ax^2+bx+c=0

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: a\neq0).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

-2x^2+4x-3=0

Therefore, you can identify that the values of "a", "b" and "c" are the following:

a=-2\\b=4\\c=-3

4 0
3 years ago
Read 2 more answers
What is the answer for this question
stich3 [128]
Inscribed ..........
5 0
3 years ago
Find the value of x.<br><br> A.<br> 10<br> B.<br> 12<br> C.<br> 27<br> D.<br> 43.5
PIT_PIT [208]

Answer:

C. 27

Step-by-step explanation:

well we can use the pythagorean theorem for this and disregard the 11. so we have the hypotenuse and one side so therefore a^2+b^2=c^2 and if we plug in the numbers it would look like this

16.5^2+x^2=29^2

272.25+x^2=841

x^2=568.75

and from multiple choice we can infer that the answer is obviously bigger than 16.5 because in the picture x is a longer side but it is smaller than 29 and the only answer in between those two numbers given would be C. 27

4 0
2 years ago
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