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Kay [80]
2 years ago
10

write the equaion of a line in slope-intercept form if the slope is 1/5 and the y-intercept is -9 explain please

Mathematics
1 answer:
faust18 [17]2 years ago
7 0

Answer:

y = \frac{1}{5} x - 9

Step-by-step explanation:

The slope-intercept form is y = mx + b, where:

m = slope

b = y-intercept.

The slope (m) tells you the steepness of the line. It is the average rate of change which measures how the y-value changes for each one-unit change in the x-value. Hence, slope = \frac{rise}{run}.  So the given slope of 1/5 means that for every 1 unit change in the y-value, the x-value changes by 5 units (you go up 1 unit, and "run" 5 units to the right).

Next, the y-intercept is the point on the graph where it crosses the y-axis, and has the coordinates, (0, b). It is also the value of y when x = 0. Since you're given the y-intercept of -9, then that means that it is the y-coordinate of (0, <em>b</em>). So, it becomes (0, -9).

Now that we have our slope (<em>m </em>) = 1/5, and the y-intercept (<em>b </em>) = -9, we can write the equation of the line as:

y = \frac{1}{5} x - 9

(I'm also including a screenshot of the line where it shows the y-intercept of (0, -9) on the graph).  

Please mark my answers as the Brainliest if you find my explanations helpful :)

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Use the drop-down menus to complete the proof. by the unique line postulate, you can draw only one segment,
Doss [256]

The reflection of BC over I is shown below.

<h3>What is reflection?</h3>
  • A reflection is a mapping from a Euclidean space to itself that is an isometry with a hyperplane as a set of fixed points; this set is known as the reflection's axis (in dimension 2) or plane (in dimension 3).
  • A figure's mirror image in the axis or plane of reflection is its image by reflection.

See the attached figure for a better explanation:

1. By the unique line postulate, you can draw only one line segment: BC

  • Since only one line can be drawn between two distinct points.

2. Using the definition of reflection, reflect BC over l.

  • To find the line segment which reflects BC over l, we will use the definition of reflection.

3. By the definition of reflection, C is the image of itself and A is the image of B.

  • Definition of reflection says the figure about a line is transformed to form the mirror image.
  • Now, the CD is the perpendicular bisector of AB so A and B are equidistant from D forming a mirror image of each other.

4. Since reflections preserve length, AC = BC

  • In Reflection the figure is transformed to form a mirror image.
  • Hence the length will be preserved in case of reflection.

Therefore, the reflection of BC over I is shown.

Know more about reflection here:

brainly.com/question/1908648

#SPJ4

The question you are looking for is here:

C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the unique line postulate, you can draw only one segment, Using the definition of, reflect BC over l. By the definition of reflection, C is the image of itself and is the image of B. Since reflections preserve , AC = BC.

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Step-by-step explanation:

The problem statement tells you exactly what the transformations are.

The first transformation is reflection across line m.

The second transformation is rotation about point A'.

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These are both rigid transformations, so ΔABC ≅ A'B''C''.

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