Question

The base of an isosceles triangle is 4/3. The perimeter of the triangle is 4 2/15. What is the length of either of the remaining sides?

Answer 1

Answer:

The answer to your question is 1$\frac{2}{5}$

Step-by-step explanation:

Data

base = 4/3

Perimeter = 4 2/15

length of the sides = ?

Process

1.- Convert the perimeter into an improper fraction

 $4\frac{2}{15} = \frac{60 + 2}{15} = \frac{62}{15}$

2.- Subtract 4/3 from 62/15

    $\frac{62}{15} - \frac{4}{3}$

    $\frac{62}{15} - \frac{20}{15}$       Multiply 4/3 by 5

    $\frac{42}{15}$

3.- Divide the result by 2 to find the length of one side

    $\frac{42}{15} / \frac{2}{1}$

4.- Result

   $\frac{42}{30}$

-Simplify

   $\frac{7}{5}$   or 1 2/5