Answer:
Rounded to the nearest hundredths: 11.69.
Step-by-step explanation:
I would use the Pythagorean theorem for this problem.
The difference between the highest point and the lowest point of AD is 9.8-7.2 = 2.6, so that would be the height of the triangle. The length/base of the triangle would be 11.4.
Now, just solve using Pythagorean's theorem:
Rounded to the nearest hundredths: 11.69.
I hope this helped you.
Answer: y=-13/12x-7
Step-by-step explanation:
To find the slope-intercept form, we first need to find the slope. To find the slope, you use the formula . We use the two given points to find the slope.
Now that we have our slope, we can start filling out the slope-intercept form equation.
y=mx+b
y=-13/12x+b
Since we don't know the y-intercept, we can use one of the given points and solve for b.
6=(-13/12)(-12)+b [multiply (-13/12) and -12]
6=13+b [subtract both sides by 13]
b=-7
With the y-intercept, we can complete our equation.
y=-13/12x-7
Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]
→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
