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PSYCHO15rus [73]
3 years ago
9

How do i solve by using substitution​

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

a = 0, b = 3

Step-by-step explanation:

3a + b = 3

b = - 3a +3

2a - 5b = - 15

2a - 5(-3a + 3) = - 15

2a + 15a - 15 = - 15

17a = 0

a = 0

b = -3a +3 = - 3 *0 +3 = 3

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What is the equation of the line that passes through the point (-6, -6) and has a<br> slope of - 1/3
pickupchik [31]

Answer:

The equation of the line is y = -\frac{1}{3}x - 8

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Slope of - 1/3

This means that m = -\frac{1}{3}

So

y = -\frac{1}{3}x + b

Through the point (-6, -6)

This means that when x = -6, y = -6. So

y = -\frac{1}{3}x + b

-6 = -\frac{1}{3}(-6) + b

b + 2 = -6

b = -8

The equation of the line is y = -\frac{1}{3}x - 8

5 0
3 years ago
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pashok25 [27]

Answer:

(Look at image)

Step-by-step explanation:

(Also look at image)

5 0
2 years ago
a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh
sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

h=-16t^2+32t+48

Let us assume that we need to find the time by it to reach the ground. It means h = 0

-16t^2+32t+48=0

The above is a quadratic equation. The value of t is given by :

t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s

So, it will take 2.11 seconds to reach the ground.

6 0
3 years ago
Students in an environmental science class raised money to buy plants for a community garden. The students raised money by selli
finlep [7]

Answer:

50 gluten-free cupcakes and 100 regular cupcakes.

Step-by-step explanation:

Let's define the variables:

R = number of regular cupcakes sold

G = number of gluten-free cupcakes sold

The total amount of money raised then is:

M = R*$2.00 + G*$3.00

We also know that:

The number of regular cupcakes sold was 2 times the number of gluten-free cupcakes sold.

then:

R = 2*G

And we also know that the amount of money raised is $350

Then we have the equations:

R = 2*G

R*$2.00 + G*$3.00 = $350

We can replace the first equation into the second one, so we have only one variable:

(2*G)*$2.00 + G*$3.00 = $350

Now we can solve this for G.

G*$4.00 + G*$3.00 = $350

G*$7.00 = $350

G = $350/$7.00 = 50

G = 50

50 gluten-free cupcakes where sold.

And using the equation:

R = 2*G = 2*50 = 100

We can conclude that 100 regular cupcakes were sold.

3 0
2 years ago
Combine like terms. 3y+6+2y-3-6y^2+7y^2-4
Anna35 [415]
Y^2+5y+10
To 2 Squared go together the regular y go together and then normal go together
8 0
3 years ago
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