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3 years ago

How do i solve by using substitution

Mathematics

1 answer:

elena55 [62]3 years ago

3 0

Answer:

a = 0, b = 3

Step-by-step explanation:

3a + b = 3

b = - 3a +3

2a - 5b = - 15

2a - 5(-3a + 3) = - 15

2a + 15a - 15 = - 15

17a = 0

a = 0

b = -3a +3 = - 3 *0 +3 = 3

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WILL GIVE BRAINLIEST! PLEASE HELP! URGENT!

Artemon [7]

Vertical Asimtote: (x-3) this will be the denominator

Horizontal Asymtote: (x-1)^2 (x+3) this will be the numerator

y= a (x-1)^2 (x+3) / (x-3)

Vertical: (x-1/2)

Horizontal: (x-3)

y= a (x-1/2)/(x-3)

I hope this helped?

7 0

3 years ago

Read 2 more answers

Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that

Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is $P(x_1 + x_2 \ge 2 )= 0.5940$

Step-by-step explanation:

From the question we are told that

The rate at which fire breaks out every 10 years is $\lambda = 1$

Generally the probability distribution function for Poisson distribution is mathematically represented as

$P(x) = \frac{\lambda^x}{ k! } * e^{-\lambda}$

Here x represent the number of state which is 2 i.e $x_1 \ \ and \ \ x_2$

Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

$P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 + x_2 \le 1 )$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [ P(x_1 = 0 , x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)$

=> $P(x_1 + x_2 \ge 2 ) = 1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}$

=> $P(x_1 + x_2 \ge 2 )= 1- [[0.3678 * 0.3679] + [0.3678 * 0.3679] + [0.3678 * 0.3679] ]$

$P(x_1 + x_2 \ge 2 )= 0.5940$

3 0

3 years ago

HELP! PLEASE! I really need help with this question!

LekaFEV [45]

Answer:

They are at the same height at 1.13 seconds.

Step-by-step explanation:

Remark

The rockets are at the same height when f(x) = g(x) [see below] are the same. So you can equate them.

Givens

f(x) = - 16x^2 + 74x + 9

g(x) = -16x^2 + 82x I have changed this so you don't have 2 f(x)s

Solution

f(x) = g(x)
-16x^2 + 74x + 9 = -16x^2 + 82x Add: 16x^2 to both sides
-16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x Combine terms
74x + 9 = 82x Subtract 74x from both sides
74x - 74x + 9 = 82x - 74x Combine
9 = 8x Divide by 8
9/8 = 8x/8
x = 1 1/8 Convert to decimal
x = 1.125
x = 1.13 [rounded]

6 0

3 years ago

I try to look this up and people said yes or no I just need a straight answer

Anna11 [10]

start inside the square root, replace X with -7.

-7 + 11 = 4

The number 4 comes out of the square root as 2.

Now there's a minus factor out there. Let's multiply this negative factor by 2 and get -2.

Now let's add -2 and -3.

Our output is -5.

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3 years ago

Find the equation of the line thatcpasses through (3, 1) and is parallel to y=1-2x.

Anna11 [10]

Slope of y=1-2x is -2
Using point intercept form:
y-1=-2(x-3)
y-1=-2x+6
y=-2x+7

5 0

2 years ago

How do i solve by using substitution​

How do i solve by using substitution